1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sattari [20]
3 years ago
14

A ballerina weighs 103 lbs and is up on her toes with only 10.0 cm2 of her slippers in contact with the floor. What pressure is

she exerting on the floor?
Chemistry
2 answers:
Ahat [919]3 years ago
8 0

Answer:

A

Explanation:

1 lb = .453 kg...so...103 x .453 = 46.72 kg  

you then multiply that by the force of gravity which is 9.8(m/s2)...so...  

46.72 x 9.8 = 458 newtons(kg x m/s^2), which is the force.  

pressure (in pascals) = Force(N) / Area (m2)  

we need to convert 10cm2 to m2 which = .001m^2  

458 / .001 = 458000 = 4.58 x 10^5 Pa

Kazeer [188]3 years ago
7 0

Options for the question;

A. 4.59 × 105 Pa

B. 4.59 × 103 Pa

C. 4.59 × 101 Pa

D. 4.59 × 10ˉ1 Pa

E. 4.59 × 10ˉ3 Pa

Answer:

Pressure = 458000 = 4.58 x 10^5 Pa; Option A

Explanation:

Bringing out the parameters in the question;

Weight = 103 lbs = 46.72 kg (Upon conversion by diving by 2.205)

Area occupied = 10.0 cm2 = 0.001m2 (Upon conversion by dividing by 10000)

Pressure = ?

The relationship between pressure and Area is given as;

Pressure (in pascals) = Force(N) / Area (m2)

Force = Mass * Gravity = 46.72 * 9.8 = 458 N

Pressure = 458 / 0.001 = 458000 = 4.58 x 10^5 Pa

You might be interested in
Which is an unreliable source?
vodomira [7]

Answer:

I believe CDC I s the most reliable

6 0
3 years ago
In which grouping of the periodic table do the elements have simliar properties
STatiana [176]
I would have to say [c]

but it could also be [b]

3 0
3 years ago
Read 2 more answers
The pH of a solution prepared by the addition of 100mL 0.002M HCL to 100mL distilled water is closest to:
IRISSAK [1]

Answer:

d.3.0

Explanation:

Step 1: Calculate the final volume of the solution

The final volume is equal to the sum of the volumes of the initial HCl solution and the volume of distilled water.

V₂ = 100 mL + 100 mL = 200 mL

Step 2: Calculate the final concentration of HCl

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂ = 0.002 M × 100 mL/200 mL = 0.001 M

Step 3: Calculate the pH of the final HCl solution

Since HCl is a strong acid, [H⁺] = HCl. We will use the definition of pH.

pH = -log [H⁺] = -log 0.001 = 3

7 0
3 years ago
What is the maximum mass of aluminum chloride that could be obtained from 6 mol of barium chloride?
kodGreya [7K]
You have to find the stoichiometric ratio between AlCl₃ and BaCl₂. The common element between them is Cl. So, the ratio of Cl in BaCl₂ to AlCl₃ is 2/3. The molar mass of AlCl₃ is 133.34 g/mol. The solution is as follows:

Mass of AlCl₃ = (6 mol BaCl₂)(2 mol Cl/1 mol BaCl₂)(1 mol AlCl₃/3 mol Cl)(133.34 g/mol) = 533.36 g AlCl₃
8 0
3 years ago
The raw water supply for a community contains 18 mg/L total particulate matter. It is to be treated by addition of 60 mg alum (A
s344n2d4d5 [400]

Solution :

Given :

The steady state flow = 8000 $ m^3 /d $

                                    $= 80 \times 10^5 \ I/d $

The concentration of the particulate matter = 18 mg/L

Therefore, the total quantity of a particulate matter in fluid $= 80 \times 10^5 \ I/d \times 18 \ mg/L $

$= 144 \times 10^6 \ mg/g$

$= 144 \ kg/d $

If 60 mg of alum $ [Al_2(SO_4)_3.14 H_2O] $ required for one litre of the water treatment.

So Alum required for  $ 80 \times 10^5 \ I/d $

$= 80 \times 15^5 \ I/d  \times 60 \ mg \ alum /L$

$= 480 \times 10^6 \ mg/d $

or 480 kg/d

Therefore the alum required is 480 kg/d

1 mg of the alum gives 0.234 mg alum precipitation, so 60 mg of alum will give $ = 60 \times 0.234 \text{ of alum ppt. per litre} $

      $= 14.04 $ mg of alum ppt. per litre

480 kg of alum will give = 480 x 0.234 kg/d

                                        = 112.32 kg/d ppt of alum

Daily total solid load is  $= 144 \ kg/d + 112.32 \ kg/d$

                                       = 256.32 kg/d

So, the total concentration of the suspended solid after alum addition $= 18 \ mg/L + 60 \times 0.234 $

= 32.04 mg/L

Therefore total alum requirement = 480 kg/d

b). Initial pH = 7.4

 The dissociation reaction of aluminium hydroxide as follows :

$Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^{-} $

After addition, the aluminium hydroxide pH of water will increase due to increase in $ OH^- $ ions.

Therefore, the pH of water will be acceptable range after the addition of aluminium hydroxide.

c). The reaction of $CO_2$ and water as follows :

$CO_2 (g) + H_2O (l) \rightarrow H_2CO_3$

For the atmospheric pressure :

$p_{CO_2} = 3.5 \times 10^{-4} \ atm $

And the pH is reduced into the range of 5.9 to 6.4

6 0
2 years ago
Other questions:
  • If 20.6 grams of ice at zero degrees Celsius completely change into liquid water at zero degrees Celsius, the enthalpy of phase
    12·1 answer
  • A coordination complex is made up of _________________________________________. (Choose one) Selected Answer: IncorrectC. a tran
    8·1 answer
  • Cómo puedes medir un gas?
    6·1 answer
  • Which type of decay does not involve the decaying atom's atomic number to change?
    9·1 answer
  • Which of the following is a norm or value that sports may socialize children about
    6·1 answer
  • Which of the following best describes the formation of plasma?
    6·1 answer
  • A sample of carbon dioxide gas that has a volume of 14.6 L at STP contains how many
    6·1 answer
  • plz help me asap (plz don't give me helpless answer plz and ty) and also ill give brainist to the person that work hard
    14·1 answer
  • Please help me.. i would appreciate it.. 50 points and will mark brainliest
    7·2 answers
  • Please Help I need an explanation on how to do this
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!