How fast do differnt parts of the em spectrum travel in a vaccuum
1 answer:
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Answer:
i) The pressure acting on the base of <em>B</em> will be half the pressure acting on the base of <em>A</em>
ii) The pressure acting on the base of <em>B</em> will be the same as the pressure acting on the base of <em>A</em>
iii) The pressure on the base of drum <em>A</em> will be slightly less than the pressure on the base of drum <em>B</em>
Explanation:
The pressure acting on the base of the drum, P = h·ρ·g
Where;
h = The level of the liquid in the drum
= The height of the drums
ρ = The density of the liquid in the drum
g = The acceleration due to gravity ≈ 9.81 m/s²
i) If <em>A</em> is completely filled, we have =
Therefore, =
×
×g
If <em>B</em> is half filled, we have, = (1/2)·
= (1/2) ×
×
×g
Therefore, = (1/2) ×
The pressure acting on the base of <em>B</em> will be half the pressure acting on the base of <em>A</em>
ii) If both <em>A</em> and <em>B</em> are each filled with water (the same liquid), then the pressure on their bases will be =
×
×g =
, the same, given that the acceleration due to gravity, <em>g</em>, is constant and the same in Nepal and India
iii) If <em>A</em> is filled with water, and <em>B</em> is filled with salty water, we have that, the density of salty water is slightly higher than water, therefore, we get;
=
×
×g <
=
The pressure on the base of drum <em>A</em> will be less than the pressure on the base of drum <em>B.</em>