Answer:3.92475J
Explanation:
ideal gas equation
PV=nrT
P=pressure
V=volume 9*5*14=630m^3
n=mole
Mole=mass/molecular mass
molecular mass of air=28.1g/mol
R=gas constant
T=temperature in kelvin
1.01*10^5*630=(m/28)*8.314j/molK *273K
784959.5677356082g
784.95kg
Kinetic energy=0.5*m*v^2
Velocity of air
0.5*784.95kg*0.1^2
K.E=3.92475J
6
Answer:
L = 2.83 J.s
Explanation:
The formula for the angular momentum of the stone is given as follows:
L = mvr
where,
L = angular momentum of the stone = ?
m = mass of the stone = 0.1 kg
v = linear velocity of the stone = rω
r = radius of circular path = 1.5 m
ω = angular speed of the stone = (2 rev/s)(2π rad/1 rev) = 4π rad/s
Therefore,
L = mvr = m(rω)r
L = mr²ω
using values, we get:
L = (0.1 kg)(1.5 m)²(4π rad/s)
<u>L = 2.83 J.s</u>
The force used to kick the ball is 1000N
The mass of the ball is 0.8 kg
Time is 0.8 seconds
Therefore the velocity can be calculated as follows
F= Mv-mu/t
1000= 0.8(v) - 0.8(0)/0.8
1000= 0.8v- 0.8/0.8
Cross multiply both sides
1000(0.8) = 0.8v
800= 0.8v
divide both sides by the coefficient of v which is 8
800/0.8= 0.8v/0.8
v= 1000m/s
Hence the velocity is 1000m/s
Answer: 45000 m/s^2
Explanation:
First, we know:
Bullet's Initial Velocity (Vo) = 0 m/s
Distance Travelled (D) = 1 m
Final Velocity (Vf) = 300 m/s
We need to know the bullets acceleration to reach the final velocity on that distance. Because the bullet stars from rest, his Initial Velocity is equal to zero.
We dont know on how much time it takes for the bullet, but we know the acceleration on the barrel is constant.
We can use the following equation for this
Because Vo is zero, the equation simplify, so we have.
Searching for the accelaration we obtain
Changing values
This is the acceleration needed to reach the velocity at the end of the barrel.