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Sholpan [36]
3 years ago
12

Since sinusoidal waves are cyclical, a particular phase difference between two waves is identical to that phase difference plus

a cycle. For example, if two waves have a phase difference of \frac{\pi}{4}, the interference effects would be the same as if the two waves had a phase difference of \frac{\pi}{4} + 2\pi. The complete criterion for constructive interference between two waves is therefore written as follows:
{\rm phase\ difference} = 0 + 2 \pi n \qquad {\rm for\ any\ integer}\ n
Write the full criterion for destructive interference between two waves.

Physics
1 answer:
poizon [28]3 years ago
3 0

Answer:

For destructive interference phase difference is

(2n+1)\pi where n∈ Whole numbers

Explanation:

For sinusoidal wave the interference affects the resultant intensity of the waves.

In the given example we have two waves interfering at a phase difference of \frac{\pi}{4} would lead to a constructive interference giving maximum amplitude at at the RMS value of the amplitude in resultant.

Also the effect is same as having a phase difference of  ( \frac{\pi}{4} + 2\pi) because after each 2π the waves repeat itself.

<em>In case of destructive interference the waves will be out of phase i.e. the amplitude vectors will be equally opposite in the direction at the same place on the same time as shown in figure.</em>

They have a phase difference of \pi or which is same as (2\pi+\pi)

Generalizing to:

a phase difference of (2n+1)\pi where n∈ {W}

{W}= set of whole numbers.

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A basketball is shot. After the ball leaves the player's hand, in which direction does the ball accelerate?
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3 years ago
A 970-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,
vlabodo [156]

Answer:

22.73 m/s or 81.72 kph

Explanation

We can find the combined mass of both cars as

970 kg + 2300 kg = 3270 kg.

Then the normal force of the cars can be calculated as

F(n)= mg

Where g is acceleration due to gravity 9.8m/s^2

3270 kg ×9.8 = 32046 kg*m/s^2.

coefficient of kinetic friction between tires and road to be 0.80 × F(n)

Then the frictional force can be calculated as

= (32046kg*m/s^2 × 0.80 )

= 25636.8 kg*m/s^2

We can now calculate the work done that was used stopping the cars as

Frictional force × distance

(25636.8 kg*m/s^2 ) × 2.9m= 74346.72kg*m^2/s^2

From kinetic energy formula, the combined velocity of the car can be determined

E=0.5 M V²

√(2E/M) = V

√(2*74346.72kg*m^2/s^2 / 3270 kg) = V

V= √ (45.472)

V=6.743293m/s

the momentum of both cars can be determined as

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= 22050.57kg*m/s

Now the final momentum of both cars must be equal to the the momentum of

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=(22050.57 kg*m/s) / 970 kg = 22.73 m/s

We can convert that to km/h.

22.73 m/s * 3600 s/h / 1000 m/km = 81.72 kph

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3 years ago
A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
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Fibers of the sweater lose electrons because electrons are leave it.

One of the ways of charging a body is by friction. Charges are transferred from one body to another when an object is rubbed against another. This is charging by friction.

A sweater has negative charges hence when the balloon is rubbed against the sweater, fibers of the sweater lose electrons because electrons are leave it.

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4 0
2 years ago
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