Question

Consider the chemical equations shown here.

Answer 1

P₄0₆$_{s}$ + 20₂$_{g}$   ⇒    P₄0₁₀$_{s}$

Explanation:

The overall equation for the reaction that produces  P₄0₁₀ is :

P₄0₆$_{s}$ + 20₂$_{g}$   ⇒    P₄0₁₀$_{s}$

Now let us derive this equation:

Given equations:

   P₄$_{s}$ + 30₂$_{g}$  ⇒ P₄0₆$_{s}$  equation 1;

   P₄$_{s}$ + 50₂$_{g}$ ⇒  P₄0₁₀$_{s}$  equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

            P₄0₆$_{s}$ ⇒ P₄$_{s}$ + 30₂$_{g}$   equation 3

                      +

            equation 2:

 P₄$_{s}$ + 50₂$_{g}$  +    P₄0₆$_{s}$  ⇒  P₄0₁₀$_{s}$  +  P₄$_{s}$ + 30₂$_{g}$  

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

   

                  P₄0₆$_{s}$ + 20₂$_{g}$   ⇒    P₄0₁₀$_{s}$

learn more:

Net equation brainly.com/question/2947744

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