Answer:
Coefficient of friction.
Explanation:
The amount of friction divided by the weight of an object is equal to the coefficient of friction. It is a dimensional less number. It can be given by :
![F=\mu N](https://tex.z-dn.net/?f=F%3D%5Cmu%20N)
N is normal force.
= coefficient of friction
![\mu=\dfrac{F}{N}](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7BF%7D%7BN%7D)
The minimum number of tickets that could admit all of them is six (6).
This thing is impossible to explain in words, so I shall attempt it with a diagram:
Here are the six ladies:
( A ) ( B )
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| |
( C ) ( D )
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( E ) ( F )
-- 'E' and 'F' are the daughters of 'C' and 'D' .
-- 'C' and 'D' are the daughters of 'A' and 'B' .
So look what we have now:
-- 'A' and 'B' are the mothers of 'C' and 'D' .
There's 2 of the mothers.
-- 'C' and 'D' are the mothers of 'E' and 'F' .
There's the OTHER 2 mothers.
-- 'A' and 'B' are the grandmothers of 'E' and 'F' .
There's the 2 grandmothers.
-- 'E' and 'F' are the daughters of 'C' and 'D' .
There's 2 of the daughters.
-- 'C' and 'D' are the daughters of 'A' and 'B' .
There's the OTHER 2 daughters.
You want to know what ? !
The group is even bigger than THAT.
There are also 2 GRAND-daughters in the family ... 'E' and 'F' .
So now you have a list of 12 people ! ... 4 mothers, 2 grandmothers,
4 daughters, and 2 grand-daughters ... and they all get in to the
Christmas Market with only six tickets. Legally !
Such a deal !
Don't forget : Christmas this year is also the first day of Chanukah !
All for the same price !
Answer:
The answer is first one 1...
Answer:
v = 9.936 m/s
Explanation:
given,
height of cliff = 40 m
speed of sound = 343 m/s
assuming that time to reach the sound to the player = 3 s
now,
time taken to fall of ball
![t = \sqrt{\dfrac{2s}{g}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cdfrac%7B2s%7D%7Bg%7D%7D)
![t = \sqrt{\dfrac{2\times 40}{9.8}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%2040%7D%7B9.8%7D%7D)
t = 2.857 s
distance
d = v x t
d = v x 2.875
time traveled by the sound before reaching the player
![t_0 = t - t_{fall}](https://tex.z-dn.net/?f=t_0%20%3D%20t%20-%20t_%7Bfall%7D)
![t_0 = 3 - 2.875](https://tex.z-dn.net/?f=t_0%20%3D%203%20-%202.875)
![t_0 = 0.143 s](https://tex.z-dn.net/?f=t_0%20%3D%200.143%20s)
distance traveled by the wave in this time'
r = 0.143 x 343
r= 49.05 m
now,
we know.
d² + h² = r²
d² + 40² = 49.05²
d =28.387 m
v x 2.875=28.387 m
v = 9.936 m/s