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SCORPION-xisa [38]
3 years ago
12

In 10s a car accelerates 4m/s^2 to 60m/s. How fast was the car going before it accelerated?

Physics
1 answer:
slega [8]3 years ago
3 0

v2 = v1 + at 60 = v1 + 4*10  v1 = 20 m/s

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Lerok [7]

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = \frac{1}{f}

where

f = focal length

Thus

f = \frac{1}{P}

f = \frac{1}{2} = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

where

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\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}

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Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm

7 0
3 years ago
Which best explains the direction of the moving force of air?. . A.. from warm temperatures to cold temperatures. . B.. from are
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Answer:

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Explanation:

hope this helps!

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What would happen if a solid temperature increases
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