A. I looked it up and it should be somewhere around A
C. The canoe's path will be a diagonal line from northeast to southwest.
Explanation:
We can solve this problem by using vector addition rules.
In fact, we know that:
- The velocity of the canoe has a component in the south direction, due to the velocity of the river which points towards south
- The canoe itself is trying to go from the eastern shore towards the western shore --> this means that the canoe has also a component of the velocity in the west direction
This means that the resultant velocity of the canoe must be in a direction intermediate between the directions of its two components: therefore, in the southwest direction.
Therefore, this means that
C. The canoe's path will be a diagonal line from northeast to southwest.
Learn more about vector addition:
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Answer:
Explanation:
From the question we are told that:
Weight 
Altitude 
Let
Radius of Earth 
Gravity 
Generally the equation for Gravity at altitude is mathematically given by
Therefore
Weight at sea level
Weight at 6.33 altitude
Therefore
Answer:
<em>Ecologist</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em>Your</em><em> </em><em>answer </em><em>is</em><em> </em><em>Ecologist</em><em>.</em>
Answer:
The frequency does not depend on the amplitude for any (ideal) mechanical or electromagnetic waves.
In electromagnetism we have that the relation is:
Velocity = wavelenght*frequency.
So the amplitude of the wave does not have any effect here.
For a mechanical system like an harmonic oscillator (that can be used to describe almost any oscillating system), we have that the frequency is:
f = (1/2*pi)*√(k/m)
Where m is the mass and k is the constant of the spring, again, you can see that the frequency only depends on the physical properties of the system, and no in how much you displace it from the equilibrium position.
This happens because as more you displace the mass from the equilibrium position, more will be the force acting on the mass, so while the "path" that the mass has to travel is bigger, the mas moves faster, so the frequency remains unaffected.
