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4 years ago

Write examples of adaptation in mangrove .? what are the adaptation of rainforest.?

Physics

1 answer:

Sergio039 [100]4 years ago

6 0

Answer:

example of adaptation in mangrove

Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.

adaptation of rainforest

Many animals have adapted to the unique conditions of the tropical rainforests.

hope this can help you

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3 years ago

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3. Liquid nitrogen at 90 K, 400 kPa flows into a probe used in a cryogenic survey. In the return line the nitrogen is then at 16

devlian [24]

Answer:

Specific heat transfer = 236.16 kJ/kg

Ratio of return velocity to inlet velocity = 0.80

Explanation:

Given

Temperature of liquid nitrogen, T1 = 90 K

Pressure of liquid nitrogen, P1 = 400 kPa

Temperature of nitrogen, T2 = 160 K

Pressure of nitrogen, T2 = 400 kPa

A(e) = 100 A(i)

To solve, we use the formula

h(i)+ 1/2v(i)² + q = h(e) + 1/2v(e)² + q

The mass flow is

m = m(i) = m(e)

m = (Av/V)i = (Av/V)e

Ratio of return velocity to inlet velocity is

v(e) / v(i) = A(i)/A(e) * V(e)/V(i)

v(e) / v(i) = 1/100 * V(e)/V(i)

From the saturated Nitrogen table, at 100 K, we have

h(i) = h(f) = -73.2

v(i) = v(f) = 0.001452

From the saturated Nitrogen table again, at 160 K and 400 kPa

h(e) = 162.96 kJ/kg

v(e) = 0.11647 m³/kg

Substituting these in the formula, we have

v(e) / v(i) = 1/100 * 0.11647/0.001452

v(e) / v(i) = 1/100 * 80.2

v(e) / v(i) = 0.80

Energy equation is given by

q + h(i) = h(e)

q = h(e) - h(i)

Now, calculating specific heat transfer

q = 162.96 - -73.2

q = 236.16 kJ/kg

6 0

3 years ago

A 0.40 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frict

nirvana33 [79]

Answer:

Part a)

$F = 26.7 N$

Part b)

$a = 66.7 m/s^2$

Explanation:

Part a)

Force on the object due to spring force is given as

$F = kx$

here we know that

$k = 157 N/m$

$x = 0.17 m$

so we have

$F = 157\times 0.17$

$F = 26.7 N$

Part b)

Acceleration of the object is given as

$a = \frac{F}{m}$

$a = \frac{26.7}{0.40}$

$a = 66.7 m/s^2$

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3 years ago

A frequency generator sends a 550 Hz sound wave through both water and ice. What is the difference in wavelength between the wav

viva [34]

3.1m is the answer your looking for

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3 years ago

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that

loris [4]

Questions Diagram is attached below

Answer:

$T=2.08s$

Explanation:

From the question we are told that:

Speed of Train $V=3.0m.s$

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Width of window $w_w=2.0m$

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$d_a=6.23$

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Time Required to travel trough d is mathematically given as

$T=\frac{d_a}{v}$

$T=\frac{6.23}{3}$

$T=2.08s$

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3 years ago

Write examples of adaptation in mangrove .? what are the adaptation of rainforest.?​

Write examples of adaptation in mangrove .? what are the adaptation of rainforest.?