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Gre4nikov [31]
3 years ago
12

A 50.0 mL sample if 0.0500 M Ca(OH)2 is added to 10.0 mL of 0.0200M HNO3. How many miles of excess acid or base are present?

Chemistry
1 answer:
kogti [31]3 years ago
7 0
Ca(OH)2+2HNO3=Ca(NO3)2+2H20

M =   \frac{n}{V}  \:


0.05= \frac{x}{0.05}  \\ x =0.0025 \: mol \: of \: Ca(OH)2 \:
0.02 =  \frac{y}{0.01} \\ y = 0.002 \: mol \: of \: HNO3 \:

HNO3 acid is limit
so,
0.0005 mol of Ca(OH)2 is excess
or
0.037 g of Ca(OH)2 is excess
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Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required grams of HCl by firstly identifying the limiting reactant via the moles of each reactant as they are in a 1:1 mole ratio:

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