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Gre4nikov [31]
3 years ago
12

A 50.0 mL sample if 0.0500 M Ca(OH)2 is added to 10.0 mL of 0.0200M HNO3. How many miles of excess acid or base are present?

Chemistry
1 answer:
kogti [31]3 years ago
7 0
Ca(OH)2+2HNO3=Ca(NO3)2+2H20

M =   \frac{n}{V}  \:


0.05= \frac{x}{0.05}  \\ x =0.0025 \: mol \: of \: Ca(OH)2 \:
0.02 =  \frac{y}{0.01} \\ y = 0.002 \: mol \: of \: HNO3 \:

HNO3 acid is limit
so,
0.0005 mol of Ca(OH)2 is excess
or
0.037 g of Ca(OH)2 is excess
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