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Gre4nikov [31]
3 years ago
12

A 50.0 mL sample if 0.0500 M Ca(OH)2 is added to 10.0 mL of 0.0200M HNO3. How many miles of excess acid or base are present?

Chemistry
1 answer:
kogti [31]3 years ago
7 0
Ca(OH)2+2HNO3=Ca(NO3)2+2H20

M =   \frac{n}{V}  \:


0.05= \frac{x}{0.05}  \\ x =0.0025 \: mol \: of \: Ca(OH)2 \:
0.02 =  \frac{y}{0.01} \\ y = 0.002 \: mol \: of \: HNO3 \:

HNO3 acid is limit
so,
0.0005 mol of Ca(OH)2 is excess
or
0.037 g of Ca(OH)2 is excess
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To convert moles to particles or grams to particles, let us have a firm understanding of what a mole is.

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The particle can be atoms, molecules, formula units, electrons, protons, neutrons, etc.

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2 years ago
PLEASE HELP
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Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

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2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

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