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mr_godi [17]
3 years ago
14

Help me please (~ ̄- ̄)~​

Chemistry
2 answers:
tankabanditka [31]3 years ago
6 0

The favourable conditions for melting of ice is

<h2>High Pressure</h2>

Since the ice has lower density than water, melting of ice involves reduction in volume. So the increase in pressure favours the process and this process is endothermic.

That's why high pressure favors this process

kirill [66]3 years ago
5 0

option 2

high pressure

ur ans(~ ̄- ̄)~

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The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh
Vinil7 [7]

Answer:

Here's what I get  

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}

3. Check:

Compare the final concentration with the original

\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}

7 0
3 years ago
The volume of 1.0 g of nitrogen in a balloon is increased, it causes
Contact [7]

The volume of 1.0 g of nitrogen in a balloon is increased. It causes: the mass of the gas to decrease the density of the gas to increase and the pressure of the gas to decrease the temperature of the gas decrease.

<h3>What is volume?</h3>

How much space an object or substance takes up.

If you increase the temperature of the gas in the balloon, the pressure will initially increase.  The balloon will expand until the pressure inside drops back down and is equal to the pressure outside.

If you increase the atmospheric pressure, the balloon will compress until the pressure inside equals the new pressure outside.

If you remove gas from the balloon, the pressure will drop, causing the balloon to compress until the pressure is again equal to the pressure outside.

if you place the balloon underwater, it will be under greater pressure, causing the balloon to compress until the inside pressure equals the new outside pressure.

Learn more about the volume here:

brainly.com/question/1578538

#SPJ1

7 0
2 years ago
Help me solve. this is science. Which one is it
Vladimir [108]

Answer:

d is the correct answer i think

7 0
3 years ago
How does the vapor pressure of water at 10 c compare with its vapor pressure at 50 c?
Paha777 [63]
The vapor pressure of water at 50ºC will be greater than that at 10ºC because of the added energy and thus greater movement of the water molecules. If one knows the ∆Hvap at a given temperature, one can calculate the vapor pressure at another temperature. This uses the Clausius-Clapeyron (sp?) equation. It turns out the vapor pressure of water at 10º is 9.2 mm Hg, and that at 50º is 92.5 mm Hg.
4 0
3 years ago
How many neutrons does element ex have if it's atomic number is 58 and it's mass numbers 156
MariettaO [177]
It would have 98 neutrons.

Explanation:
The formula for finding neutrons when given the atomic number and the mass is to do (mass - atomic number.) In this case, the mass is 156 and the atomic number is 58. So we subtract 156 - 58, which gives us 98. Therefore, it would have 98 neutrons.
4 0
3 years ago
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