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jeka57 [31]
3 years ago
11

The electric field strength E is measured as:

Physics
1 answer:
soldi70 [24.7K]3 years ago
4 0
The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>E= \frac{F}{q}
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
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Answer:

u = 104.68 m/s

Explanation:

given,

horizontal distance = 150 m

elevation of  12.4 m

angle = 8.6°

horizontal motion = x = u cos θ. t .............(1)

vertical motion =

y = u sin \theta - \dfrac{1}{2}gt^2................(2)

from equation(1) and (2)

y = x tan \theta - \dfrac{gx^2}{2u^2cos^2\theta}..........{3}

12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}

\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29

\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2

u = \sqrt{10959.34}

u = 104.68 m/s

The initial speed of the ball is u = 104.68 m/s

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3 years ago
If the weight of 1kg is 10 N in water what is the density of the stone<br>​
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Q = 8.82 × 10⁶ J

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2 years ago
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Answer:

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Substituting 2.99x10^8 m/s for s and 3.012x10^-12 m for w then

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