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jeka57 [31]
3 years ago
11

The electric field strength E is measured as:

Physics
1 answer:
soldi70 [24.7K]3 years ago
4 0
The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>E= \frac{F}{q}
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
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What is the gradual process through which humans change from birth to<br> adulthood?
Whitepunk [10]

Answer:

Growth and Development

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2 years ago
What amount of energy is needed for an electron to jump from n = 1 to n = 4?
liberstina [14]

Answer:

E=2.04\times 10^{-18}\ J

Explanation:

We need to find the energy for an electron to jump from n = 1 to n = 4.

The energy in transition from 1 state to another is given by :

E=\dfrac{-2.18\times 10^{-18}}{n^2}\ J

The difference in energy for n = 1 to n = 4 is:

E=-2.18\times 10^{-18}\times (\dfrac{1}{4^2}-1)\\\\E=2.04\times 10^{-18}\ J

So, the required energy is equal to 2.04\times 10^{-18}\ J.

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3 years ago
Arrange the balls in order from greatest amount of gravitational potential energy to least
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F e d b c a
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6 0
3 years ago
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A solid disk has a mass of 162 kg and a radius of 1.30m. This
RideAnS [48]

Answer:

754.3 m

Explanation:

The moment of inertia of the solid disk:

I = mR^2/2

Where m is the disk mass and R is the radius of the disk.

I = 162*1.3^2/2 = 136.89 kgm^2

The angular kinetic energy of the disk is then:

E_k = I\omega^2/2 = 136.89 * 18^2/2 = 22176.18 J

By law of energy conservation, this energy is converted to potential energy to pick up the 3kg block

let g = 9.8 m/s2

E_p = m_bgh = 22176.18 J

where m_b = 3 kg is the mass of block

3*9.8h = 22176.18

h = \frac{22176.18}{3*9.8} = 754.3 m

8 0
2 years ago
A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.
sasho [114]

Let the angle be Θ (theta)

Let the mass of the crate be m.

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Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

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a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

a = 2.7244 - 2.44608

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Hence, the acceleration is 0.278 m/s^2

7 0
3 years ago
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