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vekshin1
2 years ago
14

Explain why thermal and electrical conductivity is so high with copper.

Physics
1 answer:
guajiro [1.7K]2 years ago
3 0

Answer:

Free electrons

Explanation:

Copper is a lattice of positive ions with free electrons moving between them

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When the temperature of the air is 50°C, the velocity of a sound wave traveling through the air is approximately?
noname [10]

The answer is:

C. 361 m/s

The explanation:

To calculate  the speed of sound at a given temperature (50°C) we are going to use this formula:

v = 331 + 0.6T

when V is the velocity

and T is the temperature = 50°C

by substitution:

v = 331 + 0.6(50)

v = 361 m/s

So, The correct answer is C.

because of the variation of the motion of the molecules of air with change of temperature so, the velocity (V) of the  sound in the air is change with temperature.

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How does electricity flow?​
Irina-Kira [14]

Answer:C

Explanation:

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Ahmad was moving to the south with v= 10 km/hr ,and Mohammed was moving with half of Ahmad's speed to the North . Write the vect
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Answer:

5 north

Explanation:

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3 years ago
Suppose a vector V makes an angle ϕ with respect to the y axis. Part A What could be the x and y components of the vector V ? Ex
mina [271]
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3 years ago
Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 65
guajiro [1.7K]

Answer:

She must be launched with minimum speed of <u>57.67 m/s</u> to clear the 520 m gap.

Step-by-step explanation:

Given:

The angle of projection of the projectile is, \theta =65°

Range of the projectile is, R=520 m.

Acceleration due to gravity, g=9.8\ m/s^2

The minimum speed to cross the gap is the initial speed of the projectile and can be determined using the formula for range of projectile.

The range of projectile is given as:

R=\frac{v_{0}^2\sin2\theta}{g}

Plug in all the given values and solve for minimum speed, v_0.

520=\frac{v_{0}^2\sin(2(65))}{9.8}\\520\times 9.8=v_{0}^2\sin(130)\\5096=1.532v_{0}^2\\v_0^2=\frac{5096}{1.532}\\v_0^2=3326.371\\v_0=\sqrt{3326.371}=57.67\textrm{ m/s}

Therefore, she must be launched with minimum speed of 57.67 m/s to clear the 520 m gap.

3 0
3 years ago
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