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3 years ago

An airplane flies 33 m/s due east while experiencing a tailwind

Physics

1 answer:

Mazyrski [523]3 years ago

4 0

Explanation:

Use Pythagorean theorem.

v² = vₓ² + vᵧ²

(35.11 m/s)² = (33 m/s)² + vᵧ²

vᵧ = 12 m/s

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Help FAST PLSS!!!

Vesna [10]

Answer:1.) 2 seconds

2.) 4.5 hertz

3.) it will become one third is original value

4.)5.9 seconds

5.)0.87 meters

Explanation:

4 0

3 years ago

Two 10-cm-diameter charged rings face each other, 25 cm apart. The left ring is charged to ? 25 nC and the right ring is charged

MArishka [77]

Answer:

A) E = 0N/C

B) 0i + 0^^j

C) F = 0N

D) 0^i + 0^j

Explanation:

You assume that the rings are in the zy plane but in different positions.

Furthermore, you can consider that the origin of coordinates is at the midway between the rings.

A) In order to calculate the magnitude of the electric field at the middle of the rings, you take into account that the electric field produced by each ring at the origin is opposite to each other and parallel to the x axis.

You use the following formula for the electric field produced by a charge ring at a perpendicular distance of r:

$E=k\frac{rQ}{(r+R^2)^{3/2}}$ (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C

Q: charge of the ring

r: perpendicular distance to the center of the ring

R: radius of the ring

You use the equation (1) to calculate the net electric field at the midpoint between the rings:

$E=k\frac{rQ}{(r^2+R^2)^{3/2}}-k\frac{rQ}{(r^2+R^2)^{3/2}}=0\frac{N}{C}$

The electric field produced by each ring has the same magnitude but opposite direction, then, the net electric field is zero.

B) The direction of the electric field is 0^i + 0^j

C) The magnitude of the force on a proton at the midpoint between the rings is:

$F=qE=q(0N/C)=0N$

D) The direction of the force is 0^i + 0^j

6 0

3 years ago

What type of drawing is shown in the figure?

Rasek [7]

$Question$

What type of drawing is shown in the figure?

Answer:

Hi, There! My Answer would Be A. Block diagram Or C. panel Diagram!

Hope this helps! ♚♛♕♔ッ✨♚

$-xXxAnimexXx-$

6 0

3 years ago

On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the

EastWind [94]

Answer:

ω = √(2T / (mL))

Explanation:

(a) Draw a free body diagram of the mass. There are two tension forces, one pulling down and left, the other pulling down and right.

The x-components of the tension forces cancel each other out, so the net force is in the y direction:

∑F = -2T sin θ, where θ is the angle from the horizontal.

For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m). (This is derived by solving a second order differential equation.)

In this case, k = 2T/L, so the frequency is:

ω = √((2T/L) / m)

ω = √(2T / (mL))

6 0

4 years ago

What does the slope of the curve on a distance vs time graph represent?

Lilit [14]

Slope of a curve Y plotted against X is mathematically given as

$slope = \frac{dy}{dx}$

now here we can see that if similarly graph is plotted against distance and time then slope is given as

$slope = \frac{dx}{dt}$

here we can say that above is ratio of small distance and very small interval of time.

so here we can say that this ratio of distance and time for very small interval of time is known as instantaneous speed of the object which is falling freely under gravity.

So here slope of the graph will represent the speed at a given instant.

6 0

3 years ago