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Over [174]
3 years ago
13

An airplane flies 33 m/s due east while experiencing a tailwind

Physics
1 answer:
Mazyrski [523]3 years ago
4 0

Explanation:

Use Pythagorean theorem.

v² = vₓ² + vᵧ²

(35.11 m/s)² = (33 m/s)² + vᵧ²

vᵧ = 12 m/s

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A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N, how much area is in contact with the ground?
lara [203]

Pressure = (total force) / (Area)

10,000 Pa = (1,000 N) / (Area)

Multiply each side by (Area) :

(10,000 Pa) x (Area) = 1,000 N

Divide each side by (10,000 Pa) :

Area = (1,000 N) / (10,000 Pa)

<em>Area = 0.1 m² </em>

4 0
3 years ago
Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.300 m. The engine of th
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Answer:

740 N

Explanation:

We are given that

Radius,r=0.3 m

Torque,\tau=222 Nm

We have to find the magnitude of the static frictional force.

According to question

Torque by engine=Torque by static friction

222=f\times r

f=\frac{222}{r}

f=\frac{222}{0.3}

f=740 N

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8 0
3 years ago
Help pls.!! and explain please
umka2103 [35]

Answer:

so if it's 20 you should put 20 times 10 15 * 30 and 1.3 * 5 mg and if you put that milligrams in there it'll solve the destination I saw the white way you going so yeah just be careful at least you want to make the milligrams even a multimacy with the y i and replace it with the 14a

7 0
3 years ago
A woman drops a vibrating tuning fork, which is vibrating at 513 Hertz, from a tall building. Through what distance (in m) has t
umka21 [38]

Answer:

h = 15.34 m

Explanation:

given,

tuning fork vibration = 513 Hz

speed of sound = 343 m/s

frequency after deflection = 489 Hz

the source (the fork) moves away from the observer, its speed increases and hence the apparent frequency decreases

f_{apparent} = \dfrac{v}{v+u}f_0

489 = \dfrac{343}{343+u}\times 513

0.953 = \dfrac{343}{343+u}

343+u = \dfrac{343}{0.953}

343+u = 359.92

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height of the building

v² = u² + 2 g s

16.92² = 2 x 9.8 x h

h = 14.61 m

time taken by sound to reach observer

t = \dfrac{14.61}{343}

t =0.0426\ s

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h' = u t + \dfrac{1}{2}gt^2

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total distance

      h = 14.61 + 0.73

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6 0
3 years ago
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