<span>The answer is curie.
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B is the answer. It is the steepest
Answer:
that is my answer hope it helps you out
Explanation:
i got 1.40 for my answer
From the given observations,
You can see that as the concentration is doubled, half-life is halved.
That is,half-life is inversely proportional to concentration
As t( half-life) ~ 1/a^(n-1)
For this case n = 2,second order reaction.
R = k X a^n
Using the above formula you will get the rate and rate constant.