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4 years ago

The reaction has at least two reactants and one product

Physics

1 answer:

astra-53 [7]4 years ago

4 0

Answer:

I think synthesis reaction, because the reaction has two or more simple substances to form a combination with a complex substance.

Explanation:

If you need more information, please ask.

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Can someone please help me and i will give brainliest if i can.

noname [10]

Answer:

Because 1 change in one factor can effect the other and that one can effect the other and so on and so on.

So, let's just say water were to stop flowing, how would the oceans take that? How would precipitation take it?

7 0

3 years ago

Triangle XYZ has vertices X(0, 2), Y(4, 4), and Z(3, –1). Graph △XYZ and its image after a rotation of 180° about (2, –3).

Alla [95]

The image of the triangle is to be formed by rotating ΔXYZ 180 degrees about the (2, -3) as shown in the graph.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Triangle XYZ has vertices X(0, 2), Y(4, 4), and Z(3, –1).

If the triangle is ΔXYZ. Then the image of the triangle is to be formed by rotating ΔXYZ 180 degrees about the (2, -3) as shown in the graph.

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

6 0

2 years ago

When a driver presses the brake pedal, his car stops with an acceleration of -0.5 m/s². How far will the car travel while coming

Katyanochek1 [597]

Answer:

64 m

Explanation:

Using the following symbols

x: distance

v: velocity

a: constant acceleration

t: time

v₀: initial velocity

x₀: initial position

The equations of motion for a constant acceleration are given by:

(1) x = 0.5at²+v₀t+x₀

(2) v = at+v₀

From equation (2) you can calculate the time t it takes the car to come to a complete stop.

(3) t = (v-v₀)/a

Now you plug equation (3) in equation(1):

(4) x = 0.5a((v-v₀)/a)²+v₀((v-v₀)/a)+x₀

In equation (4) the position x is the only unknown.

8 0

3 years ago

A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat

Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

$\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}$

$\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}$

$\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}$

Using Newton's second law, it is established that F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object $\left(m_{1}+m_{2}\right)$

Now consider both $\mathrm{m}_{1} \text { and } \mathrm{m}_{2}$ as a system, so net force acting on the system is $\text { Force }=\left(m_{1}+m_{2}\right) a$