Answer:
50 J
Explanation:
Work, W=Fd where F is the applied force and d is the distance
Substituting 10 N for F and 5 m for d then work done on the book can be expressed as
W=10 N* 5 m=50 Nm= 50 J
Therefore, the work done is equivalent to 50 J
No. "Shuttle" has been pretty much used to indicate shuttling
between Earth and Earth-orbit.
The devices that have tooled around on the surface of Mars
have been referred to as "rovers". That was also the nickname
of the buggy on which the Apollo astronauts moved around on
the Moon in the early 1970s ... the "lunar rover".
The stretch of the spring is
The constant of the spring is k=15 N/m, so we can find the force produced by the weight by using Hook's law:
Answer:
The magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.
Explanation:
The initial centripetal acceleration, a of the race-car around the circular track of radius , R with a linear speed v is a = v²/R.
When the linear speed of the race-car increases to v' = 4v, the centripetal acceleration a' becomes a' = v'²/R = (4v)²/R = 16v²/R.
So the centripetal acceleration, a' = 16v²/R.
To know how much the magnitude of the car's centripetal acceleration changes, we take the ratio a'/a = 16v²/R ÷ v²/R = 16
a'/a = 16
a' = 16a.
So the magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.
Speed is the distance traveled
time
but velocity is the change in distance
time
