Answer:
1.21 times
Explanation:
The energy of a wave is proportional to the square of the amplitude of the wave.
Mathematically:
![E\propto A^2](https://tex.z-dn.net/?f=E%5Cpropto%20A%5E2)
where
E is the energy of the wave
A is its amplitude
In this problem, the amplitude of the wave increases by a factor of 1.1; it means that the new amplitude can be written as
![A'=1.1 A](https://tex.z-dn.net/?f=A%27%3D1.1%20A)
Therefore, this means that the energy of the wave increases by a factor:
![E'\propto A'^2=(1.1 A)^2 = 1.1^2 A^2 =1.21 A^2 = 1.21 E](https://tex.z-dn.net/?f=E%27%5Cpropto%20A%27%5E2%3D%281.1%20A%29%5E2%20%3D%201.1%5E2%20A%5E2%20%3D1.21%20A%5E2%20%3D%201.21%20E)
Therefore, the energy of the wave increases by a factor 1.21.
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01
AgCl: 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
Solving for the limiting reactant one needs to get the mols CaCl2 and mols AgNO3:
CaCl2: 0.150M(mol/L) * 0.03L = 0.0045 moles
AgNO3: 0.100M*0.015L = 0.0015 moles
Since the stoichiometric ratio of AgNO3 to CaCl2 is 2:1
0.0015 mols AgNO3 *(1 mol CaCl2/ 2 mols AgNO3) = 0.00075 mols CaCl2
Since the answer is lesser than CaCl2 then the limiting reactant is AgNO3.
To get the mass of AgCl one will do a stoichiometric calculation with respect to the limiting reactant, AgNO3.
0.0015 moles AgNO3 *
Answer: Hmmmmm that's crazy....
There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.
Fraction remaining (FR) = 0.5n
n = number of half lives that have elapsed
In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).
0.0156 = 0.5n
log 0.0156 = n log 0.5
-1.81 = -0.301 n
n = 6.0 half lives have elapsed
Explanation:
Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)
Answer:
A. ![\lambda_0=2.196\times 10^{-7}\ m](https://tex.z-dn.net/?f=%5Clambda_0%3D2.196%5Ctimes%2010%5E%7B-7%7D%5C%20m)
Explanation:
The work function of the Platinum =
For maximum wavelength, the light must have energy equal to the work function. So,
Where,
h is Plank's constant having value
c is the speed of light having value
is the wavelength of the light being bombarded
Thus,
![\frac{9.05}{10^{19}}=\frac{19.878}{10^{26}\lambda_0}](https://tex.z-dn.net/?f=%5Cfrac%7B9.05%7D%7B10%5E%7B19%7D%7D%3D%5Cfrac%7B19.878%7D%7B10%5E%7B26%7D%5Clambda_0%7D)
![9.05\times \:10^{26}\lambda_0=1.9878\times 10^{20}](https://tex.z-dn.net/?f=9.05%5Ctimes%20%5C%3A10%5E%7B26%7D%5Clambda_0%3D1.9878%5Ctimes%2010%5E%7B20%7D)
![\lambda_0=2.196\times 10^{-7}\ m](https://tex.z-dn.net/?f=%5Clambda_0%3D2.196%5Ctimes%2010%5E%7B-7%7D%5C%20m)
In my opinion yes, as of now, almost anyone could get there hands on lets say an explosive. Have you heard of dynamite fishing? It is illegal, but it is still done once people have access to dynamite, then what ends up happening not only do marine wildlife get killed but it pollutes the water and lessens the chance of the natural cycle of life. Also there are several other factors, firstly, what will you do with an explosive once you get your hands on it? Perhaps you could just use an explosive for fun/personal entertainment...that isn't right and it could harm people. So, to conclude the harder it is for people to access explosives or even acclerants the better...and to add this can be possible by making people get like some sort of licence to use them, and let them be trained in certain conditions so that there is no regrets once they have access to them. I know my idea sounds far fetched but its a thought!