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MrRa [10]
3 years ago
13

Define the word isotope​

Chemistry
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

Isotope, one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behaviour but with different atomic masses and physical properties.

svet-max [94.6K]3 years ago
4 0

Answer:

Isotopes are two or more types of atoms with the same atomic number but differing nucleon numbers due to varying numbers of neutrons in their nuclei.

OAmalOHopeO

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When a metal bonds with a nonmetal, the bond that is formed is a(n) ___.
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Ionic Bond, which is the transfer of electrons of a metal to a non-metal. 
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Explain how mass and energy are conserved when water evaporates.
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<span>The water molecules that are evaporationg absorb heat energy from the surrounding environment, which causes the evaporation. If 5 grams of water evaporate, then there will be 5 grams of water vapor in the air.

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What is the mole fraction of solute in a 3.19 m aqueous solution?
Bumek [7]
Molality= mol/ Kg

if we assume that we have 1 kg of water, we have 3.19 moles of solute. 

the formula for mole fraction --> mole fraction= mol of solule/ mol of solution

1) if we have 1 kg of water which is same as 1000 grams of water. 

2) we need to convert grams to moles using the molar mass of water 

molar mass of H₂O= (2 x 1.01) + 16.0 = 18.02 g/mol

1000 g (1 mol/ 18.02 grams)= 55.5 mol

3) mole of solution= 55.5 moles + 3.19 moles= 58.7 moles of solution

4) mole fraction= 3.19 / 58.7= 0.0543 
4 0
3 years ago
What is the expected mass (in kg) of a 10 over 5 B isotope? 1 proton = 1.6726 × 10-27 kg 1 neutron = 1.6749 × 10-27 kg A.1.67 ×
Ira Lisetskai [31]
^{10}_5 B
An atom of this isotope contains 5 protons and 10-5=5 neutrons.

5 \times 1.6726 \times 10^{-27} + 5 \times 1.6749 \times 10^{-27} = \\&#10;8.363 \times 10^{-27} + 8.3745 \times 10^{-27}= \\&#10;16.7375 \times 10^{-27}= \\&#10;1.67375 \times 10^{-26} \approx \\&#10;1.67 \times 10^{-26}

The answer is A. 1.67 × 10⁻²⁶ kg.
8 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
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