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max2010maxim [7]
3 years ago
5

Which will not appear in the equilibrium constant expression for the reaction below?

Chemistry
1 answer:
enot [183]3 years ago
6 0

Answer:

[C]

General Formulas and Concepts:

<u>Chemistry</u>

<u>Kinetics</u>

  • Rate Laws

<u>Equilibrium</u>

  • Equilibrium Expressions

Explanation:

Equilibrium Expressions are only written for either aqueous solutions or gases. Solids and liquids are negligible for equilibrium. Our equilibrium constant expression would be \displaystyle K = \frac{[CO][H]}{[H_2O]}.

∴ Carbon C (s) is not included in the expression and is our answer.

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Lady_Fox [76]

Answer:

5 in celcius is 41 in fahrenheit!

Explanation:

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Ferrous ammonium sulfate is what kind of test method.
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3 0
2 years ago
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
W
DerKrebs [107]

Answer:

F = 30 N

Explanation:

Given data:

Mass of toy train = 1.5 kg

Acceleration of train = 20 m/s²

Amount of force acting on it = ?

Solution:

The net force on object is equal to the its mass multiply by its acceleration.

Formula:

F = ma

F = force

m = mass

a = acceleration

Now we will put the values in formula.

F = 1.5 kg × 20ms⁻²

F = 30 kg.ms⁻²

kg.ms⁻² = N

F = 30 N

7 0
3 years ago
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