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max2010maxim [7]
3 years ago
5

Which will not appear in the equilibrium constant expression for the reaction below?

Chemistry
1 answer:
enot [183]3 years ago
6 0

Answer:

[C]

General Formulas and Concepts:

<u>Chemistry</u>

<u>Kinetics</u>

  • Rate Laws

<u>Equilibrium</u>

  • Equilibrium Expressions

Explanation:

Equilibrium Expressions are only written for either aqueous solutions or gases. Solids and liquids are negligible for equilibrium. Our equilibrium constant expression would be \displaystyle K = \frac{[CO][H]}{[H_2O]}.

∴ Carbon C (s) is not included in the expression and is our answer.

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You have a sample of 75.6 g of C3H8. How many moles of C3H8 are in the sample?
dsp73

The number of moles that are contained in the given mass of propane (C_3H_8 is 1.7143 moles.

<u>Given the following data:</u>

  • Mass of propane = 75.6 grams.

<u>Scientific data:</u>

  • The molar mass of propane = 44.1 g/mol.

To calculate the number of moles that are contained in the given mass of propane (C_3H_8):

<h3>How to calculate the moles of a compound.</h3>

In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:

Mathematically, the number of moles contained in a chemical compound is given by this formula:

Number\;of\;moles = \frac{mass}{molar\;mass}

Substituting the given parameters into the formula, we have;

Number\;of\;moles = \frac{75.6}{44.1}

Number of moles = 1.7143 moles.

Read more on number of moles here: brainly.com/question/3173452

3 0
2 years ago
A mixture of hydrogen and argon gases is maintained in a 6.47 L flask at a pressure of 3.43 atm and a temperature of 85 °C. If t
11Alexandr11 [23.1K]

Answer:

The mixture contains 8.23 g of Ar

Explanation:

Let's solve this with the Ideal Gases Law

Total pressure of a mixture = (Total moles . R . T) / V

We convert T° from °C to K → 85°C + 273 = 358K

3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L

(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles

0.756= Total moles from the mixture

Moles of Ar + Moles of H₂ = 0.756 moles

Moles of Ar + 1.10 g / 2g/mol = 0.756 moles

Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206

We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g

8 0
3 years ago
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Increasing order of unsaturation
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Whats the question? Im not sure what your asking

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What volume of a 0.232 M hydrobromic acid solution is required to neutralize 10.8 mL of a 0.162 M potassium hydroxide solution?
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