A book is launched up along the rough incline. Kinetic energy given to a book at initial point is 100 J. Book comes to stop at s
1 answer:
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Answer:
(a) Work done by the tension force is 987 J
(b) Coefficient of kinetic friction between the crate and surface is 0.495
Explanation:
(a)
Work done by any force F in moving an object by a distance d making an angle with the direction of force is given by
Thus work done by the tension force is 987 J
(b)
Normal force on the crate is given by
=>N=332 Newtons
Since crate is moving with constant speed . Therefore using Newtons second law .
Where =coefficient of kinetic friction
=>
=>
Thus coefficient of kinetic friction between the crate and surface is 0.495
Answer:
a = - 11.53[m/s^2]
Explanation:
The airplane slows down as its speed decreases from the initial value of 610 [m/s] to zero.
To calculate the acceleration value we use the following kinematics equation:
where:
Vf = final velocity = 0
Vi = initial velocity = 610 [m/s]
a = acceleration [m/s2]
t = time = 53 [s]
Now replacing:
0 = 610 + (a*53)
-610 = 53*a
a = - 11.53[m/s^2]
The negative sign means that the aircraft is losing speed, i.e. slowing down