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Sliva [168]
3 years ago
15

3. A jet aircraft is moving at a constant speed of 500

Physics
1 answer:
garri49 [273]3 years ago
7 0

Answer:2 hours

Explanation:

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A drowsy cat spots a flowerpot that sails first up and then down past an open window. the pot was in view for a total of 0.49 s,
Alika [10]

For this case, let's assume that the pot spends exactly half of its time going up, and half going down, i.e. it is visible upward for 0.245 s and downward for 0.245 s. Let us take the bottom of the window to be zero on a vertical axis pointing upward. All calculations will be made in reference to this coordinate system. <span>

An initial condition has been supplied by the problem: 

s=1.80m when t=0.245s 

<span>This means that it takes the pot 0.245 seconds to travel upward 1.8m. Knowing that the gravitational acceleration acts downward constantly at 9.81m/s^2, and based on this information we can use the formula:

s=(v)(t)+(1/2)(a)(t^2) 

to solve for v, the initial velocity of the pot as it enters the cat's view through the window. Substituting and solving (note that gravitational acceleration is negative since this is opposite our coordinate orientation): 

(1.8m)=(v)(0.245s)+(1/2)(-9.81m/s^2)(0.245s)^2 

v=8.549m/s 

<span>Now we know the initial velocity of the pot right when it enters the view of the window. We know that at the apex of its flight, the pot's velocity will be v=0, and using this piece of information we can use the kinematic equation:

(v final)=(v initial)+(a)(t) 

to solve for the time it will take for the pot to reach the apex of its flight. Because (v final)=0, this equation will look like 

0=(v)+(a)(t) 

Substituting and solving for t: 

0=(8.549m/s)+(-9.81m/s^2)(t) 

t=0.8714s 

<span>Using this information and the kinematic equation we can find the total height of the pot’s flight:

s=(v)(t)+(1/2)(a)(t^2) </span></span></span></span>

s=8.549m/s (0.8714s)-0.5(9.81m/s^2)(0.8714s)^2

s=3.725m<span>

This distance is measured from the bottom of the window, and so we will need to subtract 1.80m from it to find the distance from the top of the window: 

3.725m – 1.8m=1.925m</span>

 

Answer:

<span>1.925m</span>

3 0
3 years ago
Two identical small charged spheres hang in equilibrium with equal masses (0.02kg). The length of the strings is equal (0.18m) a
Yuliya22 [10]

Answer:

The value is q = 3.4 *10^{-6} \ C

Explanation:

From the question we are told that

    The mass of each sphere is m_1 = m_2  = m  =  0.020 \ kg

     The length of the string is  l = 0.18 \  m

     The angle of with the vertical is \theta  =  7^o

      The acceleration due to gravity is g = 9.8 \ m/s^2

Generally the force acting between the forces is mathematically represented as

       F  =  T cos \theta =  \frac{k*  q^2}{ r^2}

=>     T cos \theta =  \frac{k*  q^2}{ r^2}

Generally from Pythagoras theorem the radius of the circular curve created by the force is

         r = 2 L sin (\theta )

=>      r = 2* 0.180 sin (7)

=>      r = 0.043 \ m  

=>     q = tan \theta * \frac{m * g * r^2 }{k}

=>      q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}

=>      q = 3.4 *10^{-6} \ C

7 0
3 years ago
A bicyclist travels 4.5 km west, then travels 6.7 km at an angle 27.0 degrees South of West. What is the magnitude of the bicycl
Dimas [21]

Answer:

<em>10.90km</em>

Explanation:

Magnitude of the total displacement is expressed using the equation

d = √dx²+dy²

dx is the horizontal component of the displacement

dy is the vertical component of the displacement

dy = -6.7sin27°

dy = -6.7(0.4539)

dy = -3.042

For the  horizontal component of the displacement

dx = -4.5 - 6.7cos27

dx = -4.5 -5.9697

dx = -10.4697

Get the magnitude of the bicyclist's total displacement

Recall that: d = √dx²+dy²

d = √(-3.042)²+(-10.4697)²

d = √9.2538+109.6146

d = √118.8684

<em>d = 10.90km</em>

<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>

<em></em>

6 0
3 years ago
A=vf-vi/t is the equation for calculating the acceleration of an object. write out the relationship shown in the equation using
Lelechka [254]
Basically it is the difference in velocity divided by the time it takes to make that change.
3 0
3 years ago
How far above the surface of earth would you weigh 71.5 percent of your surface weight?
kramer
Hey, Name's Jessy. I hope, I answer your question.

Nearly 400 lbs,by 11.73%.
4 0
3 years ago
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