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2 years ago

1) What are the parts of a longitudinal wave? How are they different? ***

Physics

1 answer:

Kay [80]2 years ago

3 0

Answer:

Compression- pushing together

Refraction- pulling apart

Wavelength- the length of the wave

Explanation:

I just knew it

~Plz click the crown~

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One of the most important properties of materials in many applications is strength. Two of the qualitative measures of the stren

katrin2010 [14]

To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.

In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.

By definition we know that the tensile strength is defined as

$\sigma = \frac{F}{A}$

Where,

$\sigma =$ Tensile strength

F = Tensile Force

A = Cross-sectional Area

In the other hand we have that the shear strength is defined as

$\sigma_y = \frac{F_y}{A}$

where,

$\sigma_y =$ Shear strength

$F_y =$ Shear Force

$A_0 =$ Parallel Area

PART A) Replacing with our values in the equation of tensile strenght, then

$311*10^6 = \frac{F}{(15*10^{-6})(30*10^{-2})}$

Resolving for F,

$F= 1399.5N$

PART B) We need here to apply the shear strength equation, then

$\sigma_y = \frac{F_y}{A}$

$210*10^6 = \frac{F_y}{15*10^{-6}30*10^{-2}}$

$F_y = 945N$

In such a way that the material is more resistant to tensile strength than shear force.

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3 years ago

Adam wants to work in the field of forensic science and follow the rules for handling evidence. Which organization can he join t

Tamiku [17]

I would say its c . National Academy of Forensic Science

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2 years ago

A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th

vladimir2022 [97]

As we know that friction force on box is given by

$F_s = \mu_s N$

here we know that

$N = mg$

here we have

m = 12 kg

$\mu_s = 0.42$

so now we have

$N = 12(9.8) = 117.6 N$

now we will have

$F_s = 0.42(12)(9.8)$

$F_s = 49.4 N$

so it required minimum 49 N(approx) force to move the block

5 0

3 years ago

Read 2 more answers

What step did Mendel take to be sure that his pea plants did not self-pollinate?

Ipatiy [6.2K]

Answer:

it is made up of some theory

Explanation:

it is an artificial pollination

8 0

2 years ago

Rahman drops two stones P and Q each of mass 1 kg and 2 kg simultaneously from

kolbaska11 [484]

This question involves the use of the equations of motion for vertical motion.

The time taken by the stones P and Q to reach the ground is the same, that is "2 s".

The velocity with which Q hits the ground is "20 m/s".

The time taken by the stones to reach the ground can be calculated by using the second equation of motion for the vertical motion:

$h = v_it+\frac{1}{2}gt^2$

For both the stones P and Q:

h = height = 20 m

$v_i$ = initial velocity = 0 m/s

t = time = ?

g = acceleration due to gravity = 10 m/s²

Therefore,

$20\ m = (0\ m/s)t+\frac{1}{2}(10\ m/s^2)(t)^2\\\\t = \sqrt{\frac{20\ m}{5\ m/s^2}}$

t = 2 s

Hence, the time taken by both the stones to reach the ground is the same.

To find the final velocity of stone Q we will use the first equation of motion for the vertical motion:

$v_f=v_i+gt\\v_f = 0\ m/s+(10\ m/s^2)(2\ s)\\v_f = 20\ m/s$

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

5 0

2 years ago