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sukhopar [10]
2 years ago
13

Dolphins communicate using compression waves (longitudinal waves). Some of the sounds dolphins make are outside the range of hum

an hearing. Upon spotting a hungry shark, dolphin A sends a message to dolphin B. To send this message as effectively as possible, dolphin A would
A.make a softer sound because the shark will not hear the softer signal.
B.send the message above the water when it jumps because air is more dense than water, and the sound would be louder above the water.
C.send the message underwater because a more dense medium produces a louder sound.
D. make a higher pitched signal because a higher pitch is a louder sound. Question 2 Unsaved Compare wave A with wave B correctly in relation to amplitude.
A. Wave A will have a higher pitch than wave B
B.Wave B will have a higher pitch than wave A
C.Wave A will have a louder sound than wave B
D. Wave B will have a softer sound than wave A. Save Question 3 (2 points) Question 3 In old times, before there were train signals, people who worked on the railroad would often put their ear down to the train track to listen for an oncoming train. Why would this result in hearing the train further off than just listening for the train through the air?
A. Sound waves travel faster in more dense material, and the more dense the material the louder the sound is.
B. People did not do this because sound travels faster through less dense material, like air, rather than more dense materiel, like train tracks.
C.Sound travels slower, but louder through solid material because it is more dense, so the train could be heard better this way.
D. Sound travels slower in air because there are often trees and other items blocking the sound.
Question 4 Unsaved Sound waves are mechanical waves in which the particles in the medium vibrate in a direction parallel to the direction of energy transport. What is another name for the type of wave that transfers energy in this way?
A. longitudinal waves
B. surface waves
C. pressure waves
D. transverse waves
Question 5 Which shows the loudest sound?
A because this shows the most dense material.
B because the particles are bigger than A.
C because the particles are shown are the most dense material because they are bigger and closer together
D because these are the biggest particles, and are therefore, the most dense. Question 6 What happened to the amplitude from wave A to wave B?
A. The amplitude doubled
B.The amplitude tripled
C. The amplitude decreased
D. The amplitude didn't change
Question 7 Identify the amplitude on the diagram and give the correct description.
C because the wavelength shows amplitude.
C because amplitude is the distance from wave crest to wave crest.
D because amplitude is the distance between a crest (or trough) and rest.
D because wavelength show simplitude.
Chemistry
1 answer:
Alchen [17]2 years ago
8 0
Question 4 is <span>A. longitudinal waves </span>
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The value of the solubility product constant for Ag2CO3 is 8.5 × 10‒12 and that of Ag2CrO4 is 1.1 × 10‒12. From this data, what
Lena [83]

Answer:

B) 7.7

Explanation:

For the reaction    Ag2CO3(s) + CrO42‒(aq) → Ag2CrO4(s) + CO32‒(aq)

Kc = (CO₃²⁻) / (CrO₄²⁻)

and the Ksp given are

Ag₂CO₃    ⇒  2 Ag⁺(aq) + CO₃²⁻(aq)    Ksp₁ = (Ag⁺)²(CO₃²⁻)  

Ag₂CrO₄   ⇒  2 Ag⁺(aq)+ CrO₄²⁻(aq)   Ksp₂ = (Ag⁺)²(CrO₄²⁻)

Where (...) indicate concentrations M

Notice if we divide the expressions for Ksp we get:

Ksp₁/Ksp₂ = (CO₃²⁻)  / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7

which is the desired answer.

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3 years ago
Balance the equations​
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1. 2 H2 + O2 = 2 H2O

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3. 10 Na + 2 NaNO3 = 6 Na2O + N2

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2 years ago
Which phrase best describes activation energy? (1 point)
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Oxygen gas, generated by the reaction 2KClO3(s)---2KCl(s)+3O2(g), is collected over water at 27•C in 3.72L vassel at a total pre
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Answer:

moles = 0.093 moles

Explanation:

In this case, we know that this reaction is taking plave in a vessel that has a 730 torr of total pressure.

The total pressure is a value obtained by:

Pt = Pwater + PO2

We need to know the pressure of O2, because then, with stoichiometry, we can calculate the moles of KClO3

The pressure of oxygen is:

PO2 = 730 - 26 = 704 Torr

Now, this pressure is in Torr, and we need to convert it to Atm, so:

704 Torr / 760 Torr = 0.9263 atm

Now, let's use the ideal gas equation:

PV = nRT

With this expression, we will calculate the moles of O2, and then, the moles of KClO3:

n = PV/RT

R = 0.082 L atm /K mol

P = 0.9263 atm

V = 3.72 L

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Replacing the data:

n = 0.9263 * 3.72 / 300 * 0.082

n = 0.14 moles

Finally, by stoichiometry, we know that 2 moles of KClO3 produces 3 moles of O2, so:

moles of KClO3 = 0.14 * 2/3 = 0.093 moles of KClO3

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