Question

You are visiting a winery for a wine tasting. A large storage barrel (diameter 4.4 m) is filled to a height of 250 cm. The barrel has on its top a small hole to guarantee contact with the atmospheric pressure. The tap of the barrel is at a height of 12 cm from the bottom of the barrel. The opening of the tap faces towards you and does not point downward.If you hold your wine glass at the same height level as the bottom of the barrel, how far away from the tap do you have to hold the glass so that the wine stream hits it exactly? Answer in units of cm

Answer 1

Answer:

V = 6.83 m/s

t = 0.6969s

Explanation:

Distance (s) of wine above the tap = height of the barrel - height of the tap

S = (250 - 12)cm = 238cm

S = 2.38m

From equation of motion,

V² = u² + 2gs

Where u = initial velocity = 0m/s

g = acceleration due to gravity = 9.8m/s²

V² = 2gs

V = √(2 * 9.8 * 2.38)

v = √(46.648)

v = 6.8299 ≈ 6.83m/s

b). Time it took for the wine to reach the cup

S = ut + ½gt²

Since u = 0

S = ½gt²

T = √(2s / g)

t = √[(2 * 2.38) / 9.8]

t = 0.6969s