<span>Since the wheel start from rest. angular acceleration,
θ=1/2αt²
14=1/2α x 8.7²
α= 0.3699 rad/s²
moment of inertia of loop= mr²= 4.1x0.37=1.517 kgm²
torque=T= lα
T= 0.5611Nm= 0.56Nm to significant figure
Disc
moment of inertia of disc= 1/2mr²
Required torque value= 0.28Nm
So,
I= 1/2X 4.1X 0.37²= 0.280 Kgm²
T= Iα = 0.280 X 0.3699= 0.10 to two significant figure</span>
It's vertical position in the air at time is
where is the acceleration due to gravity. After 1.00 second has passed, its position is
Answer:
follow this steps so you can find the answer of your question
Explanation:
To calculate the centripetal force for an object travelling in a circular motion, you should:
Find the square of its linear velocity, v² .
Multiply this value by its mass, m .
Divide everything by the circle's radius, r .
A house, address, area.
I hope this helps!
The answer is D. Kelvin hope this helps