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3 years ago

How do electronegativity values help us determine the type of bond created?

1 answer:

6 0

Answer: The difference between the electronegativity or (∆EN) of two different atoms indicates the type of bond created.

Explanation: For ionic bond compounds the difference between their electronegativity is 1.7 or greater. Covalent bond compounds have a difference of 0.4 but not greater than 1.7 on their electronegativity.

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Balance the following equation. Then determine the ratio for the products KCl and O2 generated during the decomposition of potas

drek231 [11]

The answer is 2:3 for plato users

6 0

3 years ago

Read 2 more answers

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago

Help <br> whoever answers all gets marked brainliest

Lelechka [254]

See H and C have shared their electrons so it's Covalent bonding

Yes here we can see the dots and crosses clearly.

Dot and crosses digram

It's Methane or CH_4

4 single bonds

There is no double bond

6 0

3 years ago

Read 2 more answers

A measured sample of argon gas has a volume of 20.0 L at a pressure of 660 mm Hg. What is the final volume

valkas [14]

Answer:

C . 24 L

Explanation:

Given data:

Initial volume of gas = 20.0 L

Initial pressure of gas = 660 mmHg

Final volume = ?

Final pressure = 550 mmHg

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

660 mmHg × 20.0 L = 550 mmHg × V₂

V₂ = 13200 mmHg. L/ 550 mmHg

V₂ = 24 L

3 0

3 years ago

What is the final volume of a gas (in liters) when the initial volume is 14.00 L at

8_murik_8 [283]

Answer:

$V_2=1344L$

Explanation:

Hello there!

In this case, since we have a problem about volume-pressure relationship, the idea here is to use the Boyle's law to calculate the final volume as shown below:

$P_2V_2=P_1V_1\\\\V_2=\frac{P_2V_2}{P_1}\\$

Then, we plug in the initial and final pressures and the initial volume to obtain:

$V_2=\frac{14.00L*0.9600atm}{0.01000atm}\\\\V_2=1344L$

Regards!

4 0

2 years ago