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Kisachek [45]
4 years ago
13

Raul doesn’t feel like he needs to write down events that will happen months from now. Explain to him why it is important to use

the different types of calendars.
Engineering
2 answers:
MAXImum [283]4 years ago
4 0
The primary reason for having a calendar is to organize the days, weeks, months and years. It keeps a track of which day of the week events fall and when special events are going to happen. Historically speaking calendars were often uses to preserve religious holidays and events.
larisa86 [58]4 years ago
4 0

Answer: Calendars are important so that; Students know what’s coming up. Adequate time is planned for important events and studying different levels of detail are accounted for students may be organized and prepared for anything.

Explanation:

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What advantage might there be to having the encoder located on the motor side of the gearhead instead of at the output shaft of
pickupchik [31]

The most accurate answer to that process is definitely precision. The Rotary encoder is an electro-mechanical device that converts the angular position or motion of a shaft or axle to analog or digital output signals. The efficiency of these devices is subject to the position and angle of the axis in front of the encoder.

Most cars use reduction systems in their gearboxes that convert a certain signal input into an output. Mechanically for example, a 20: 1 reduction box already infers that if there is a revolution in the input at the output there are 20. That same transferred to the encoder pulses would imply greater precision.

For example a decoder with 50 holes would have to read 1000 pulses (50 * 20) which is basically a degree of accuracy of 0.36 degrees. In this way it is possible to conclude that if the assembly of the encoder is carried out next to the motor and not at the output, it can be provided with greater precision at the time of reading.

7 0
4 years ago
What unit of measurment would be used to measure current?
Alex_Xolod [135]

Answer:

The S. I unit of current is Amphere

5 0
4 years ago
Anthony and Angel are making plans for Friday. Anthony wants to go bowling. Angel doesn't bowl well and prefers to go ice-skatin
serious [3.7K]
I am mostly on the side of compromise do i think that’s the answer
4 0
3 years ago
Read 2 more answers
The magic square is an arrangement of numbers in a square grid in such a way that the sum of the numbers in each row, and in eac
Yuki888 [10]

Answer:

See the explanation for the answer;

Explanation:

Matlab code is as given below

-------------------------------------------------------------------------------------Start of code

% Program to create a magic square and verify it

clc

M= magic(5)

% To find sum of elements of each row

r1= sum(M(1,:))      % Sum of row 1

r2= sum(M(2,:))      % Sum of row 2

r3= sum(M(3,:))      % Sum of row 3

r4= sum(M(4,:))      % Sum of row 4

r5= sum(M(5,:))      % Sum of row 5

% To find sum of each coloumn

c1= sum(M(:,1))      % Sum of coloumn 1

c2= sum(M(:,2))      % Sum of coloumn 2

c2= sum(M(:,3))      % Sum of coloumn 3

c2= sum(M(:,4))      % Sum of coloumn 4

c2= sum(M(:,5))      % Sum of coloumn 5

% To find sum of diagonal

d1= sum(diag(M))               % Sum of principal diagonal elements

d2= sum(diag(fliplr(M)))      

-------------------------------------------------------------------------------End of code

Following results are obtained when executed.

M =

   17    24     1     8    15

   23     5     7    14    16

    4     6    13    20    22

   10    12    19    21     3

   11    18    25     2     9

r1 =

   65

r2 =

   65

r3 =

   65

r4 =

   65

r5 =

   65

c1 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

d1 =

   65

d2 =

   65

3 0
3 years ago
A race car is travelling around a circular track. The velocity of the car is 20 m/s, the radius of the track is 300 m, and the m
Zielflug [23.3K]

Answer:

μ = 0.136

Explanation:

given,

velocity of the car = 20 m/s

radius of the track = 300 m

mass of the car = 2000 kg

centrifugal force

F_c = \dfrac{mv^2}{r}

F_c = \dfrac{2000\times 20^2}{300}

F c = 2666. 67 N

F f= μ N

F f = μ m g

2666.67  =  μ × 2000 × 9.8

μ = 0.136

so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136

5 0
4 years ago
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