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jok3333 [9.3K]
3 years ago
12

A race car is travelling around a circular track. The velocity of the car is 20 m/s, the radius of the track is 300 m, and the m

as of the car is 2000 kg. Determine the minimum coefficient of friction between the road surface and the tires of the car in order that the car does not skid off the track.
Engineering
1 answer:
Zielflug [23.3K]3 years ago
5 0

Answer:

μ = 0.136

Explanation:

given,

velocity of the car = 20 m/s

radius of the track = 300 m

mass of the car = 2000 kg

centrifugal force

F_c = \dfrac{mv^2}{r}

F_c = \dfrac{2000\times 20^2}{300}

F c = 2666. 67 N

F f= μ N

F f = μ m g

2666.67  =  μ × 2000 × 9.8

μ = 0.136

so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136

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Explanation:

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