Some of the benefits of using measurements to find density include the following:
- It is easy and doesn't require experiments.
- The volume of both light and dense molecule can be gotten.
Some of the challenges of using measurements to find density include the following:
- Inconsistency in the grind setting
- Temperature changes not taken into account.
<h3>What is Density?</h3>
This is defined as the mass per unit volume of a substance or te degree of compactness of a substance and can be gotten with the use of measurements or experiments.
The measurement doesn't take the temperature changes into consideration which will lead to the result being most likely incorrect. It is also advantageous because less time is used thereby making it easier.
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Answer:
The answer to your question is
1.-Fe₂O₃
2.- 280 g
3.- 330 g
Explanation:
Data
mass of CO = 224 g
mass of Fe₂O₃ = 400 g
mass of Fe = ?
mass of CO₂
Balanced chemical reaction
Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂
1.- Calculate the molar mass of Fe₂O₃ and CO
Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g
CO = 12 + 16 = 28 g
2.- Calculate the proportions
theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90
experimental proportion Fe₂O₃ / CO = 400/224 = 1.78
As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.
3.- 160 g of Fe₂O₃ --------------- 2(56) g of Fe
400 g of Fe₂O₃ --------------- x
x = (400 x 112) / 160
x = 280 g of Fe
4.- 160 g of Fe₂O₃ --------------- 3(44) g of CO₂
400 g of Fe₂O₃ -------------- x
x = (400 x 132)/160
x = 330 gr
Answer: -
3-Ethyl-N,N-dimethylbenzamide.
Explanation: -
In the first step the nitrogen lone pair attacks the carbonyl carbon.
Then a OH becomes water molecule by protonation and leaves.
Final step involves proton loss to form amide.
Answer:
35.4575 amu
Explanation:
We use the relative abundance of each of the isotopes.
Let the isotopes be A and B.
Since A is having an abundance of 75.53, the abundance of B would be 100 - 75.53 = 24.47%
The average atomic mass is calculated as follows;
(75.53/100 * 34.96885) + (24.47/100 * 36.96590) = 26.4119 + 9.0456 = 35.4575 amu
Answer:
60g of LiNO3 are required
Explanation:
<em>Calculate the amount of solute, in grams or milliliters, to prepare...</em>
<em />
The percentage mass/volume %(m/v) is defined as the mass in grams of the solute in 100mL of solution
To solve this question we must know that in a 37.5% (m/v) of LiNO3 you have 37.5g of LiNO3 in 100mL of solution.
Thus, to prepare 160mL are required:
160mL * (37.5g / 100mL) =
<h3>60g of LiNO3 are required</h3>