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ale4655 [162]
3 years ago
6

How are rare earth elements important to our technological world?

Chemistry
1 answer:
Fynjy0 [20]3 years ago
4 0

Rare earth elements are a series of chemical elements found in the earth's crust and are vital to many of the modern technologies in the world such as computers and networks, advanced transportation and consumer electronics. They help fuel economic growth, maintain high living standards and even save lives. Examples include:

Scandium. Used in television and fluorescent lamps.

Yttrium. Used in cancer treatment drugs, superconductors and camera lenses

Lanthanum. Used to make special optical glasses,  telescope lenses and also in petroleum refining.

Neodymium. Used in making some of the strongest permanent magnets, found in most modern vehicles and aircraft.


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Oxygen,hydrogen, and carbon
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What is the scientific method 1-7?
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Crime scene investigators keep a wide variety of compounds on hand to help with identifying unknown substances they find in the
almond37 [142]

The powder could be acetaminophen, analgesic  having chemical formula C_{17}H_{21}NO_{4}

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.

We are given:

Percentage of C = 67.31 %

Percentage of H = 6.978 %

Percentage of N = 4.617 %

Percentage of O = 21.10 %

Let the mass of the compound be 100 g. So, the percentages given are taken as mass.

Mass of C = 67.31 g

Mass of H = 6.978 g

Mass of N = 4.617 g

Mass of O = 21.10 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of carbon = \frac{mass}{molar \;mass}

Moles of carbon =\frac{67.31g}{12g/mole}

=5.60 moles

Moles of hydrogen = \frac{mass}{molar \;mass}

Moles of hydrogen = \frac{6.978 g}{1 g/mole}

=6.978 moles

Moles of nitrogen =\frac{mass}{molar \;mass}

Moles of nitrogen = \frac{4.617  g}{14 g/mole}

=0.329 moles

Moles of oxygen =\frac{mass}{molar \;mass}

Moles of oxygen =\frac{21.10 g}{16 g/mole}

=1.31 moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.

We get the ratio of C : H : N : O = 17 : 21 : 1 : 4

The empirical formula for the given compound is C_{17}H_{21}NO_{4}.

Learn more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

3 0
2 years ago
g Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis a
Alex787 [66]

Answer:

A and B are unfavorable reactions.

Explanation:

In chemical thermodynamics, an endergonic reaction  is also called a nonspontaneous reaction or an unfavorable reaction. it's a chemical reaction in which the change in free energy is positive, and energy is absorbed.

In chemical thermodynamics, an exergonic reaction  is also called a spontaneous reaction or a favorable reaction. it's a chemical reaction in which the change in free energy is negative.

ΔG>0

If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous .

If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG=ΔH-TΔS

with ΔG= Gibbs free energy

with ΔH =  enthalpy of reaction

with T = temperature of eh reaction

ΔS = Entropy change

The reaction A: Pi+glucose⟶glucose-6-phosphate+H2O

The ΔG is positive. This is an nonspontaneous reaction or an unfavorable reaction

The reaction B: Pi+fructose-6-phosphate⟶fructose-1,6-bisphosphate+H2O

The ΔG is positive. This is an nonspontaneous reaction or an unfavorable reaction.

The reaction C: ATP+H2O⟶ADP+Pi

The ΔG is negative. This is a spontaneous reaction or a favorable reaction.

A and B are unfavorable reactions.

6 0
3 years ago
PLS HELP ASAP!! I will do brainliest!!!! PLS IMMA DIE
Bess [88]
B. combination of all wavelengths of visible light
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3 years ago
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