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Anika [276]
3 years ago
8

A 60 kg driver gets into an empty taptap to start the day's work. the springs compress 1.5Ã10â2 m . what is the effective spring

constant of the spring system in the taptap?
Physics
1 answer:
creativ13 [48]3 years ago
6 0
The force applied to the spring is the weight of the driver:
W=mg=(60 kg)(9.81 m/s^2)=588.6 N
Under this force, the spring compresses by x=1.5 \cdot 10^{-2}m. We can find the spring's constant k by using Hook's law:
F=kx
And so
k= \frac{F}{x}= \frac{588.6 N}{1.5 \cdot 10^{-2}m}=39240 N/m
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