Answer:
14 J of heat
Explanation:
Recall that the enthalpy of reaction is defined as the enthalpy change that occurs in a system when matter is transformed by a given chemical reaction, if all reactants and products are in their standard states. Here we have the heat of formation of six moles of the substance and we are expected to use it to obtain the the heat of formation of one mole of the compound and we can do that by simple proportion as shown below;
If 6 moles of the compound produces 84J of heat
1 mole of the substance will produce 1×84/6 = 14 J of heat
I think it would be better control of fusion reactions.
If I were you, I'd try to go with this one :
![[(6)(-241.8)+(5)(-393.5)]-[-35.1] =-481.6](https://tex.z-dn.net/?f=%20%5B%286%29%28-241.8%29%2B%285%29%28-393.5%29%5D-%5B-35.1%5D%20%3D-481.6)
. I think that is a solution you have to find. Just use the sum of standard enthalpies of products and <span>of reactants. Hope you will find it helpful!</span>
Answer:
the heat can be spread and store up the heat and make the temperature go higher
Explanation:
hope it helps?????