F(5) = -4(25) - 3 = -100 -3 = -103
answer
f(5) = -103
g(-5) = 3(-5) - 1 = -15 -1 = -16
answer
g(-5) = -16
Best estimate would be to round 591.3 to 600 and round 29 to 30. 600/30 = 20.
Answer:
68%
Step-by-step explanation:
The mean is 32 minutes, and the standard deviation is 4 minutes.
28 is 1 standard deviation below the mean, and 36 is 1 standard deviation above the mean.
According to the empirical rule, 68% of a normal distribution is between -1 and 1 standard deviations. 95% is between -2 and 2 standard deviations. 99.5% is between -3 and 3 standard deviations.
So the answer is 68%.
Answer:
Frog 1 - 8 feet 3 inches =
8 feet x (1 yard/3 feet) = 2.667 Yards
3 inches x (1 foot /12 inches) x ( 1 yard / 3 feet) = 0.83 yards
So Frog 1 = 2.75 Yard
Frog 2 - 2 yards 36 inches
36 inches x (1 foot /12 inches) x (1 yard / 3 feet) = 1 Yard
So Frog 2 = 3 yards
Frog 2 won
It won by 3 - 2.75 = 0.25 Yards
0.25 yards x (3 feet / 1 yard) = 0.75 feet
0.75 feet x (12 inches /1 foot) = 9 inches
<u>So Frog 2 won by 9 inches</u>
The rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t
So, given that both store A and store B follow the same equations but t is different for them, you can right:
Store A: pA (t) 10,000 (1.075)^t
Store B: pB(t'): 10,000 (1.075)^t'
=> pA(t) / pB(t') = 1.075^t / 1.075^t'
=> pA(t) / pB(t') = 1.075 ^ (t - t')
And t - t' = 0.5 years
=> pA(t) / pB(t') = 1.075 ^ (0.5) = 1.0368
or pB(t') / pA(t) = 1.075^(-0.5) = 0.964
=> pB(t') ≈ 0.96 * pA(t)
Which means that the profit of the store B is about 96% the profit of store A at any time after both stores have opened.
