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shutvik [7]
3 years ago
11

A pharmacist wishes to mix a solution that is 5% Minoxidil. She has on hand 80 ml of a 4% solution and wishes to add some 7% sol

ution to obtain the desired 5% solution. How much 7% solution should she add? ...?
Chemistry
2 answers:
Alona [7]3 years ago
6 0
<span>The 80 ml solution has (.04)(80) ml of the medicine, or 3.3 ml of medicine.The pharmacist adds V ml of 7% solution, or .07V ml of medicine. The total amoune of medicine is (.07V + 3.2) mg. The total volume of solution is (V + 80) ml, so (.07V + 3.2) / (V + 80) = .05. Solve for V.</span>
Debora [2.8K]3 years ago
6 0

The 80 ml solution has (.04)(80) ml of the medicine, or 3.3 ml of medicine.The pharmacist adds V ml of 7% solution, or .07V ml of medicine. The total amoune of medicine is (.07V + 3.2) mg. The total volume of solution is (V + 80) ml, so (.07V + 3.2) / (V + 80) = .05.

Solve for V.

<span>V = 40 ml.</span>

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During photosynthesis, plant leaves take in carbon dioxide through _______ in their leaves. a stomata b xylem c phloem
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<h3>Answer:</h3>

Stomata

<h3>Explanation:</h3>
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7 0
3 years ago
M=<br> V=432.6 mL<br> D=8.4 g/ml
Nitella [24]

Answer:

Explanation:

M=D times V

Answer-3,633.84g

Rounded Answer (correct sig figs)- 3600g

6 0
3 years ago
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5 0
3 years ago
Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.
BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = <u>240.9</u>

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = <u>144</u>

Now we can find percentage composition / percentage by mass of oxygen.

% composition = \frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound} × 100

% composition = \frac{144}{240.9} × 100 = <u>59.776%</u>

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

8 0
2 years ago
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