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antoniya [11.8K]
3 years ago
7

Post Test: Forces and Motion

Physics
1 answer:
Len [333]3 years ago
8 0

Answer: B to C

Explanation: The line is curving inwards, practically calculating the stance that it had went down. If it went straight across, it stayed the same till a specific point, furthermore calculating the bent line bending upwards is actually a partial-raise, conclude points B to C is most likely an un-even balance, meaning it had went down; or decreasing. B to C is the decreasing segment of this equation/problem (question).

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A toy rocket is launched with an initial velocity of 10.0 m/s in the horizontal direction from the roof of a 38.0-m-tall buildin
Bas_tet [7]

Answer:

Explanation:

Consider downward displacement first .

downward displacement h = 38 m .

downward acceleration = g

downward initial velocity u = 0

h = ut + 1/2 g t ²

38 = 0 + 9.8 t ²

t = 1.97 s

During this period , there will be horizontal displacement with initial velocity u = 10 m /s and acceleration a = 1.6 m /s²

s = ut + 1/2 a t²

= 10 x 1.97 + .5 x 1.6 x 1.97²

= 19.7 + 3.10

= 22.8 m

3 0
3 years ago
The table shows the potential energy and kinetic energy of a skier at two different positions on a hill.
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Answer:

30,000 units, because total energy remains unchanged

6 0
3 years ago
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A car travels 30 km north in 25 min. and 40 km east in 35 min. What is the total time in hours? Be careful to carry over the pro
inna [77]
25+35=60mins so 1.0 hours
3 0
4 years ago
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According to this graph, which statement describes how the amount of iron changes over time in the reaction
melamori03 [73]
The graph shows the production of Fe.
You can see from the graph that it increases rapidly and then slowly increases.
The answer is (A).

Cheers.
5 0
3 years ago
A 5.00-a current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. copper has 8.5 * 1028 free ele
vlada-n [284]

The correct answer is: 3.125*10^{19} electrons/second

Explanation:

5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:

Electrons per second = n_e=\frac{5}{e}=\frac{5}{ 1.60\cdot 10^{-19}}=3.125*10^{19}

7 0
3 years ago
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