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3 years ago

Post Test: Forces and Motion

Physics

1 answer:

Len [333]3 years ago

8 0

Answer: B to C

Explanation: The line is curving inwards, practically calculating the stance that it had went down. If it went straight across, it stayed the same till a specific point, furthermore calculating the bent line bending upwards is actually a partial-raise, conclude points B to C is most likely an un-even balance, meaning it had went down; or decreasing. B to C is the decreasing segment of this equation/problem (question).

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People living at Earth’s equator are traveling at a constant speed of about 1,670 km/h as Earth spins on its axis. What are thes

Vlada [557]

The people living around the equator experience acceleration. Acceleration is the change in speed or/and direction. When on a rotating body, the speed does not change it is only the direction that changes as it rotates.When on a rotating body you do not have to change speed but only direction. In a normal situation when you are traveling on a circle you will never have a straight line.

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4 years ago

you push a ball to star it rolling along a "perfectly frictionless" surface. How far will the ball roll

-BARSIC- [3]

Technically, it should roll forever.

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3 years ago

When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance

larisa [96]

Answer:

R = 28.125 ohms

Explanation:

Given that,

The voltage of a bulb, V = 4.5 V

Current, I = 0.16 A

We need to find the resistance of the filament. Using Ohm's law,

V = IR

Where

R is the resistance of the filament

So,

$R=\dfrac{V}{I}\\\\R=\dfrac{4.5}{0.16}\\\\R=28.125\ \Omega$

So, the resistance of the filament is equal to 28.125 ohms.

5 0

2 years ago

How much mass should be attached to a vertical ideal spring having a spring constant (force constant) of 39.5 n/m so that it wil

mrs_skeptik [129]

The frequency of a simple harmonic oscillator such as a spring-mass system is given by
$f= \frac{1}{2 \pi} \sqrt{ \frac{k}{m} }$
where
k is the spring constant
m is the mass attached to the spring.

Re-arranging the formula, we get:
$m= \frac{k}{4 \pi^2 f^2}$
and since we know the constant of the spring:
$k=39.5 N/m$
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
$m= \frac{39.5 Hz}{4 \pi^2 (1.00 Hz)^2} = 1.00 kg$

7 0

3 years ago

Forces always act in pairs? True or false

nasty-shy [4]

Answer:

True

Explanation:

Just as Isaac Newton says, "For every action, there is an equal and opposite reaction."

7 0

3 years ago