Answer: 5.0 moles
Explanation:
From the equation, we see that for every 4 moles of ammonia consumed, 4 moles of nitrogen monoxide are produced (we can reduce this to moles of ammonia consumed = moles of nitrogen monoxide produced).
This means that the answer is <u>5.0 mol</u>
Answer:
the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
The computation of the initial concentration of the SCN^- in the mixture is as follows:
As we know that

As it is mentioned in the question that KSCN is present 10 mL of 0.05 M
So, the total milimoles of SCN^- is
= 10 × 0.05
= 0.5 m moles
The total volume in mixture is
= 45 + 10 + 30
= 85 mL
Now the initial concentration of the SCN^- is
= 0.5 ÷ 85
= 0.00588 M
hence, the initial concentration of SCN- in the mixture is 0.00588 M
Answer:
See the answer below , please.
Explanation:
In a decomposition reaction, a certain compound is "broken" to give two or more different products.
An example for compound AB, giving as products A and B:
AB -> A + B
In the case of water:
2H20 -> 2H2 + 02, water decomposes giving Hydrogen and Oxygen
1.4 mg/dL = 0.014 g/L
Explanation:
Milligrams per deciliter to grams per liter
There is 1000 grams of mg/dL of 1 g/L