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meriva
3 years ago
13

A distance of one centimeter is the same as 100 m 10 m .01 m 1000 m

Chemistry
2 answers:
VladimirAG [237]3 years ago
6 0
The answer to the question is 0.01m
katovenus [111]3 years ago
3 0
0.01m
...................
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How can you tell if a compound is an acid or base?
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By there pH . a pH below 7 is acidic . Above 7 is basic. If it’s right at 7 it’s neutral.
6 0
2 years ago
The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the molar solubility of this compound.
mafiozo [28]
As,
                              CuCO₃    ⇆  Cu²⁺  +  CO₃²⁻
So,
                             Kc  =  [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
                             Kc (CuCO₃)  =  [Cu²⁺] [CO₃²⁻]
Or,
                             Ksp  =  [Cu²⁺] [CO₃²⁻]
As,
Ksp  = 1.4 × 10⁻¹⁰
So,
                            1.4 × 10⁻¹⁰  =  [x] [x]
Or,
                             x²  =  1.4 × 10⁻¹⁰ 
Or,
                             x  =  1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
                             x  =  1.18 × 10⁻⁵ mol/L × 123.526 g/mol

                   
         x  =  1.45 × 10⁻³ g/L
3 0
2 years ago
Write the IUPAC names for the following compounds.
atroni [7]
Benzine
Bromine
Clorine
5 0
2 years ago
The solubility of nitrogen gas at 25 degrees C and 1 atm is 6.8 x 10^(-4) mol/L. If the partial pressure of nitrogen gas in air
Zolol [24]

Answer:

5.2 x 10⁻⁴ M.

Explanation:

  • The relationship between gas pressure and the  concentration of dissolved gas is given by  Henry’s law:

<em>P = kC</em>

where P is the partial pressure of the gaseous  solute above the solution.

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas.

  • At two different pressures, there is two different concentrations of dissolved gases and is expressed in a relation as:

<em>P₁C₂ = P₂C₁,</em>

P₁ = 1.0 atm, C₁ = 6.8 x 10⁻⁴ mol/L.

P₂ = 0.76 atm, C₂ = ??? mol/L.

<em>∴ C₂ = (P₂C₁)/P₁ =</em> (0.76 atm)(6.8 x 10⁻⁴ mol/L)/(1.0 atm) = <em>5.168 x 10⁻⁴ mol/L ≅ 5.2 x 10⁻⁴ M.</em>

5 0
2 years ago
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