Explanation:
The initial concentrations for a mixture :
Acetic acid at equilibrium = 0.15 M
Ethanol at equilibrium = 0.15 M
Ethyl acetate at equilibrium = 0.40 M
Water at equilibrium = 0.40 M
Initially:
0.15 M 0.15 M 0.40 M 0.40 M
At equilibrium
(0.15-x)M (0.15-x) M (0.40+x) M (0.40+x) M
The equilibrium constant is given by expression
![K_c=\frac{[CH_3CO_2C_2H_5][H_2O]}{[CH_3COOH][C_2H_5OH]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3CO_2C_2H_5%5D%5BH_2O%5D%7D%7B%5BCH_3COOH%5D%5BC_2H_5OH%5D%7D)
Solving for x:
x = 0.0333
The equilibrium concentrations for a mixture :
Acetic acid at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M
Ethanol at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M
Ethyl acetate at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M
Water at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M
Here are the solutions:
For NaCl, there would be one electron transferred from the sodium atom, now producing a cation to the chlorine atom resulting in a chlorine anion. Forming ionic bond.
For CaS, there would be 2 electrons transferred from an atom of Ca to S, this can be obtained by simply looking at the ionic charges and or combining capacities of Ca.
For BaO, likewise, 2 electrons that are valence electrons are transferred from Ba to Oxygen.
In the ionic compound of KBr, the atom of K, potassium donated its one valence electron to Br, in need of it to achieve a stable octet, and produce the chemical bond.
Finally, LiF, a single valence electron is transferred from a metal atom of Li to F, for both of the atoms that would form the ionic bond to achieve a stable octet, and or full electron shell.
Answer:
so you can do the maths your self
Explanation:
isotopes are elements with he same proton number but difference in their neutron number
- proton number is also known as the atomic number
- mass number is the sum of the proton number and the neutron number
- mass number = proton number + neutron number
