Answer:
The least number of forces required to stretch a spring is one.
Explanation:
Let suppose that spring is ideal, that is, that effects from its mass can be neglected since it is insignificant in comparison with external forces. In addition, let the spring have a linear behavior, meaning that net external longitudinal force exerted on spring is directly proportional to defomation. (Hooke's Law) That is:
(1)
(2)
Where:
- Net external force, measured in newtons.
- Spring constant, measured in newtons per meter.
- Deformation of spring, measured in meters.
Hence, the least number of forces required to stretch a spring is one.
Answer:
Distance, d = 778.05 m
Explanation:
Given that,
Force acting on the car, F = 981 N
Mass of the car, m = 1550 kg
Initial speed of the car, v = 25 mi/h = 11.17 m/s
We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:
Let d is the distance covered by car. Using second equation of motion as :
So, the car will cover a distance of 778.05 meters.
The equation you would use here is F=ma, where F is the force in Newtons, m is the mass in kilograms (must be in kilograms in order for the units to match on both sides), and a is acceleration in meters per second squared. Therefore, you do: 65kg x .3m/s^2= FF. That'll give you the answer.