The equation of the line through (0, 1) and (<em>c</em>, 0) is
<em>y</em> - 0 = (0 - 1)/(<em>c</em> - 0) (<em>x</em> - <em>c</em>) ==> <em>y</em> = 1 - <em>x</em>/<em>c</em>
Let <em>L</em> denote the given lamina,
<em>L</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ <em>c</em> and 0 ≤ <em>y</em> ≤ 1 - <em>x</em>/<em>c</em>}
Then the center of mass of <em>L</em> is the point with coordinates given by
where is the first moment of <em>L</em> about the <em>x</em>-axis, is the first moment about the <em>y</em>-axis, and <em>m</em> is the mass of <em>L</em>. We only care about the <em>y</em>-coordinate, of course.
Let <em>ρ</em> be the mass density of <em>L</em>. Then <em>L</em> has a mass of
Now we compute the first moment about the <em>y</em>-axis:
Then
but this clearly isn't independent of <em>c</em> ...
Maybe the <em>x</em>-coordinate was intended? Because we would have had
and we get
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
I = PRT
P = 1000
R = 2.5% or 0.025
T = 4
I = (1000)(.025)(4)
I=100
1000+100=1100
but the answer choices???
slope (m) = rate. $40 per hour is the rate, so m = 45
y-intercept (b) = one time fee. $45 is the flat rate which is the one time fee, so b = 45
y = mx + b
y = 40x + 45
Answer: A