Answer:
Partial pressure of CO2 = 16 atm
Explanation:
Total number of moles of gases = 4+1 = 5 moles
Mole fraction of CO2 = 4/5
Partial pressure of CO2 = mole fraction of CO2 × total pressure
Partial pressure of CO2 = (4/5) × 20
Partial pressure of CO2 = 16 atm
Not sure, but I would guess it's due to environmental factors, like heat, and imperfections in the metal. Just an educated guess, though.
62.5 mL is prepare .
What is molarity?
Molar concentration is a unit of measurement for the concentration of a chemical species, specifically a solute, in a solution, expressed as the amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.
Molarity of the stock solution as 0.100 M
Volume of the dilute solution as 250 mL
Molarity of dilute solution as 0.0250 M
We are required to calculate the Volume of the stalk solution.
Taking the volume and molarity of the stock solution to be V₁ and M₁ respectively, and volume and molarity of the dilute solution to be V₂ and M₂ respectively.
We are going to use the dilution formula;
According to the dilution formula, M₁V₁ = M₂V₂
Rearranging the formula;
V₁ = M₂V₂ ÷ M₁
= (0.025 M × 0.25 L) ÷ 0.100 M
= 0.0625 L
But, 1 L = 1000 mL
V₁ = 62.5 mL
Therefore, the volume of the stock solution is 62.5 mL
Learn more about molarity from given link
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An aqueous solution of an arrhenius acid reacts with an aqueous solution of an arrhenius base to produce water and salt.
<h3>What is a Salt?</h3>
This is a compound which is formed as a result of a neutralization reaction between acid and base.
Arrhenius acid reacts with an aqueous solution of an arrhenius base to produce water and salt due to increased concentration of H+ and OH- respectively.
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According to Raoult's law the relative lowering of vapour pressure of a solution made by dissolving non volatile solute is equal to the mole fraction of the non volatile solute dissolved.
the relative lowering of vapour pressure is the ratio of lowering of vapour pressure and vapour pressure of pure solvent
Where
xB = mole fraction of solute=?
p = 22.8 torr
mole fraction is ratio of moles of solute and total moles of solute and solvent
moles of solvent = mass / molar mass = 500 /18 = 27.78 moles
putting the values
mass of glucose = moles X molar mass = 1.218 X 180 = 219.24 grams
