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jeyben [28]
2 years ago
9

If a car goes from 20 miles per hour to 10 miles per hour in 5 seconds, find its acceleration

Physics
2 answers:
Assoli18 [71]2 years ago
8 0

Answer:

a = -0.89 m/s^2

Explanation:

initial speed of the car is given as

v_i = 20 miles/hour

here we know that

v_i = 20 \times \frac{1609}{3600}

v_i = 8.94 m/s

final speed of the car is given as

v_f = 10 mile/hour

v_f = 10 \times \frac{1609}{3600}

v_f = 4.47 m/s

now we have

a = \frac{v_f - v_i}{\Delta t}

a = \frac{4.47 - 8.94}{5}

a = -0.89 m/s^2

Alexandra [31]2 years ago
6 0

A= -2 due to is a desacceleration

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Explanation: Hope this helped :)

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2 years ago
Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. S
Alja [10]

Answer:

16294 rad/s

Explanation:

Given that

M(ns) = 2M(s), where

M(s) = 1.99*10^30 kg, so that

M(ns) = 3.98*10^30 kg

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F = G.M(ns).M(s) / R²(ns), where

G = 6.67*10^-11, gravitational constant

Again, centripetal force of the neutron star is given as

F = M(ns).v² / R(ns)

Recall that v = wR(ns), so that

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For a circular motion, it's been established that the centripetal force is equal to the gravitational force, hence

F = F

G.M(ns).M(s) / R²(ns) = M(s).w².R(ns)

Making W subject of formula, we have

w = √[{G.M(ns).M(s) / R²(ns)} / {M(s).R(ns)}]

w = √[{G.M(ns)} / {R³(ns)}]

w = √[(6.67*10^-11 * 3.98*10^30) / 10000³]

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3 years ago
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vazorg [7]

Answer:

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zaharov [31]

Answer:

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