Answer:
<h2>151.8 N</h2>
Explanation:
The force acting on the blimp can be found by using the formula
<h3>f = p × a</h3>
p is the pressure
a is the area
3000 cm² = 0.3 m²
From the question we have
f = 506 × 0.3
We have the final answer as
<h3>151.8 N</h3>
Hope this helps you
 
        
             
        
        
        
To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

Here,
 = Angle between areal vector and magnetic field direction.
 = Angle between areal vector and magnetic field direction. 
According to Faraday's law, induced emf in the loop is,





At time  ,  Induced emf is,
,  Induced emf is,


Therefore the magnitude of the induced emf is 10.9V
 
        
                    
             
        
        
        
A real cubic expansivity is an increase in the volume of a liquid per unit volume per degree rise in temperature when heated in an inexpansible vessel.
        
                    
             
        
        
        
<span>the easy walk harness should be looser on the dog than other harnesses</span>
        
                    
             
        
        
        
Answer:
Explanation:
Given:
U1 = 1.6 m/s
U2 = -1.1 m/s
M1 = 1850 kg
M2 = 1400 kg
V1 = 0.27 m/s
Using momentum- collision equation, 
M1U1 + M2U2 = M1V1 + M2V2 
1850 × 1.6 - 1400 × 1.1 = 1850 × 0.27 + 1400 × V2
1420 = 499.5 + 1400V2
V2 = 0.6575 m/s
B.
KE = 1/2 × MV^2
KEa1 + KEa2 = KEb1 + KEb2
Delta KE = KE2 - KE1
KEa1 = 2368 J
KEb1 = 847 J
KEa2 = 67.433 J
KEb2 = 302.6 J
KE1 = KEa1 + KEb1
= 3215 J
KE2 = 370.033 J
Delta KE = -2845 J.