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vladimir1956 [14]
4 years ago
12

Which of the following would have the largest pKa?

Chemistry
1 answer:
garri49 [273]4 years ago
5 0

Answer:

CH3CH2NH3+/CH3CH2NH2 would have the largest pKa

Explanation:

To answer this question we must know Kb of CH3CH2NH2 is 5.6x10⁻⁴, and for C6H5NH2 is 4.0x10⁻¹⁰. And the CH3CH2NH3+ and C6H5NH3+ are related with these substances because are their conjugate base. That means:

pKa of  CH3CH2NH3+ =  CH3CH2NH2;  C6H5NH3+ =  C6H5NH2

Also, Kw / Kb = Ka

Thus:

pKa of CH3CH2NH3+/CH3CH2NH2 is:

Kw / kb = Ka = 1.79x10⁻¹¹

-log Ka = pKa

pKa = 10.75

pKa of C6H5NH3+/ C6H5NH2 is:

Kw / kb = Ka = 2.5x10⁻⁵

-log Ka = pKa

pKa = 4.6

That means CH3CH2NH3+/CH3CH2NH2 would have the largest pKa

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How many moles of Cs are contained in 3 moles of Cs3PO4?
Alenkinab [10]

Answer:

\boxed {\boxed {\sf 9 \ moles \ Cs}}

Explanation:

We are given the compound: Cs₃PO₄

According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.

Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.

3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}

3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs

3 moles of cesium phosphate contains <u>9 moles of cesium.</u>

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3 years ago
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DanielleElmas [232]

Explanation:

According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.

For example, Na^{+} + Cl^{-} \rightarrow NaCl

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Sum of mass of reactants = mass of Na + mass of Cl

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Mass of product formed is as follows.

Mass of NaCl = mass of Na + mass of Cl

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As mass reacted is equal to the amount of mass formed. This shows that mass is conserved.

As a result, law of conservation of mass is obeyed.

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Add more drink mix until you notice a color change. Have you increased or decreased the concentration? (Higher number means a hi
valina [46]

Answer:

Increased the concentration

Explanation:

Complete Question

Open the simulation by pushing the play button.  Begin by dragging the concentration tester overto the liquid and add drink mix until the concentration reaches approximately 2.oo mol/L.  This means there are 2.00 moles of the drink mix in 1 Liter of the solution. Add more drink mix until you notice a color change. Have you increased or decreased the concentration? (Higher number means a higher concentration).

Solution

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Hence, in the case the concentration of the drink has been increased.

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