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4 years ago

A spherical electron cloud surrounding an atomic nucleus would best represent

Physics

1 answer:

podryga [215]4 years ago

6 0

Answer:

a S orbital

Explanation:

Atomic orbitals is the place where we are most likely to find at least one electron, this definition is based on the equation posed by Erwin Schrödinger.

It is said that each electron occupies an atomic orbital that is defined by a series of quantum numbers s, n, ml, ms. In any atom each orbital can contain two electrons. It is possible that thanks to the function of the orbitals, the appearance that atoms can have is that of a diffuse cloud.

The orbitals s (l = 0) have a spherical shape. The extent of this orbital depends on the value of the main quantum number, so a 3s orbital has the same shape but is larger than a 2s orbital.

The orbitals p (l = 1) are formed by two identical lobes that project along an axis. The junction zone of both lobes coincides with the atomic nucleus. There are three orbitals p (m = -1, m = 0 and m = + 1) in the same way, which differ only in their orientation along the x, y or z axes.

The orbitals d (l = 2) are also formed by lobes. There are five types of d orbitals (corresponding to m = -2, -1, 0, 1, 2)

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A 6.11-g bullet is moving horizontally with a velocity of 366 m/s, where the sign indicates that it is moving to the right (see

jeka94

Answer:

$V=1.86m/s$

Explanation:

Mass of bullet $M_B=6.11g$

Velocity of bullet $V_B=366m/s$

Mass of first block $M_b_1=1206g$

Velocity of block $V_b=0.662m/s$

Mass of second block $M_b_2=1550g$

Generally the total momentum before collision is mathematically given as

$P_1=0.006kg*366+0+0$

$P_1=2.196kg\ m/s$

Generally the total momentum after collision is mathematically given as

$P_2=(1.206kg*0.633)+(1.550+0.00611)V$

$P_2=0.763398+1.55611V$

Generally the total momentum is mathematically given as

$P_1=P_2$

$2.196=0.763398+1.55611V$

$V=\frac{2.196+0.763398}{1.55611}$

$V=1.86m/s$

4 0

3 years ago

A weight of 6 kg increases the speed of its force from 2 m / s to 4 m / s. By how many joules does the kinetic energy of the bod

Leviafan [203]

Answer:

36 J

Explanation:

Let's start off with the Kinetic Energy formula: 1/2m $v^{2}$

So to find the change in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.

*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the mass, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.

If 6 kg is the MASS:

Beginning: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2 = $\frac{1}{2}$ (6)(2 squared)= $\frac{1}{2}$ (6)(4)= 12 J

End: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2= $\frac{1}{2}$ (6)(4 squared)= $\frac{1}{2}$ (6)(16)= 48 J

Answer:

36 J

If 6 kg is the WEIGHT:

We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:

Weight = mass x acceleration due to gravity

6 = mass x 9.8

6 = 9.8m

*Divide both sides*

mass = 0.6 kg

Now, we can use the mass to find the kinetic energy.

Beginning: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2 = $\frac{1}{2}$ (0.6)(2 squared)= $\frac{1}{2}$ (0.6)(4)= 1.2 J

End: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2= $\frac{1}{2}$ (0.6)(4 squared)= $\frac{1}{2}$ (0.6)(16)= 4.8 J

Answer:

3.6 J

(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)

4 0

3 years ago

A 1.0-kg block and a 2.0-kg block are pressed together on a horizontal frictionless surface with a compressed very light spring

egoroff_w [7]

Answer:

4. both blocks will both have the same amount of kinetic energy.

Explanation:

When the blocks are released free from the compression force, the spring exerts equal and opposite force on each block but the block with heavier (double) mass will attain slower ( half ) speed as compared to the lighter block according to the law of inertia. This works in synchronization to energy conservation.

Spring force is given as:

$F=k.\Delta x$

where: $\Delta x=$ length of compression in the spring

We know kinetic energy is given by:

$KE=\frac{1}{2} m.v^2$

Hence the kinetic energy of both the blocks is equal when they are released to move free.

8 0

4 years ago

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

3 years ago

At highway speeds, a particular car is capable of an acceleration of about 1.6 m/s?. At this rate,

kicyunya [14]

Given parameters:

Acceleration of the car = 1.6m/s

Initial speed = 80km/hr

Final speed = 110km/hr

Solution:

Time taken to achieve this speed = ?

Solution:

Acceleration is the rate of change of velocity with the time taken.

Mathematically;

a = $\frac{V - U}{T}$

where a is the acceleration

V is the final velocity

U is the initial velocity

T is the time taken

Now make the unknown time the subject of the expression;

aT = V - U

T = $\frac{V - U}{a}$

Convert the given acceleration to km/hr;

1.6m/s = 1.6 x $\frac{m}{s}$ x $\frac{1km}{1000m}$ x $\frac{3600s}{1hr}$ = 5.76km/hr

Input the parameters and solve;

T = $\frac{110 - 80}{5.76}$ = 5.2hrs

The time taken is 5.2hrs

5 0

4 years ago