Answer:
The new force becomes 3 times of the initial force.
Explanation:
Let q₁ and q₂ are two charged particles. The force between them is given by :
If
and
Also, r' = r/2
New force,
Putting all the above values,
So, the new force becomes 3 times of the initial force.
Answer:
The constant force is 263.55 newtons
Explanation:
There's a rotational version of the Newton's second law that relates the net torque on an object with its angular acceleration by the equation:
(1)
with τ the net torque and α the angular acceleration. It’s interesting to note the similarity of that equation with the well-known equation F=ma. I that is the moment of inertia is like m in the linear case. The magnitude of a torque is defined as
with F the force applied in some point, r the distance of the point respect the axis rotation and θ the angle between the force and the radial vector that points toward the point the force is applied, in our case θ=90 and sinθ=1, then (1):
(2)
Because the applied force is constant the angular acceleration is constant too, and for constant angular acceleration we have that it's equal to the change of angular velocity over a period of time:
It's important to work in radian units so knowing that
(3)
The moment of inertia of a disk is:
(4)
with M the mass of the disk and R its radius, then
using the values (3) and (4) on (2)
(2)
Because the force is applied about the rim of the disk r=R=1.50:
Answer:
y = k/x
Explanation:
y = k/x is a graph of a hyperbola that has been rotated about the origin.
Answer:
0.39
Explanation:
distance from the center (r) = 32 cm = 0.32 m
speed of the coin (v) = 110 cm/s = 1.1 m/s
acceleration due to gravity (g) = 980 m/s^{2} = 9.8 m/s^{2}
find the coefficient of static friction (k) between the coin and the turn table
frictional force = kmg
before the table begins to move, the frictional force balances the centripetal force ()
therefore
frictional force = centripetal force
kmg =
kg =
k = ÷ g
k = ÷ 9.8 = 0.39