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maria [59]
3 years ago
13

Moving a magnet inside a coil of wire will induce a voltage in the coil. How can the voltage in the coil be increased?

Physics
2 answers:
mr_godi [17]3 years ago
5 0
As the magnet is moved inside a coil of wire, the number of lines of magnetic field passing through the coil changes. Faraday stated that : it is the change in the number of field lines passing through the the coil of wire that induces emf in the loop. Specifically, it is the rate of change in the number of magnetic field lines passing through the loop that determines the induced emf. There is a term called magnetic flux same as electric flux, this magnetic flux can be a measure of the number of field lines passing through a surface. It is given by ( Φ=ΣB. dA. Where B is magnetic field and dA is small elementary area). The induced emf is given by (ξ = dΦ/dt). This equation states that THE MAGNITUDE OF THE INDUCED CURRENT IN A CIRCUIT IS EQUAL TO THE RATE AT WHICH THE MAGNETIC FLUX THROUGH THE CIRCUIT IS CHANGING WITH TIME. So more rapid you move the coil, more will be the change in flux and hence more emf will be produced. So option D is the correct answer. I hope this long description will help you out.
Lapatulllka [165]3 years ago
5 0
_Award brainliest if helped!
The voltage produced is proportional to the rate of change of flux (magnetic field)
D. Move the magnet inside the coil of wire more rapidly.
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3 years ago
If santa slides 5.00 m before reaching the edge, what is his speed as he leaves the roof?
AveGali [126]

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8 0
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Tpy6a [65]
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8 0
3 years ago
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vlabodo [156]

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Explanation: Please see the attachments below

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Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of
vredina [299]

Answer:

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Explanation:

The equation

I\alpha  = Fd

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Therefore, the angular speed \omega which is

\omega  = \alpha t

after 6 seconds is

\omega = 244.44$\: s^{-2}* 6s

\boxed{\omega = 1466.67s^{-1}}

7 0
3 years ago
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