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maria [59]
3 years ago
13

Moving a magnet inside a coil of wire will induce a voltage in the coil. How can the voltage in the coil be increased?

Physics
2 answers:
mr_godi [17]3 years ago
5 0
As the magnet is moved inside a coil of wire, the number of lines of magnetic field passing through the coil changes. Faraday stated that : it is the change in the number of field lines passing through the the coil of wire that induces emf in the loop. Specifically, it is the rate of change in the number of magnetic field lines passing through the loop that determines the induced emf. There is a term called magnetic flux same as electric flux, this magnetic flux can be a measure of the number of field lines passing through a surface. It is given by ( Φ=ΣB. dA. Where B is magnetic field and dA is small elementary area). The induced emf is given by (ξ = dΦ/dt). This equation states that THE MAGNITUDE OF THE INDUCED CURRENT IN A CIRCUIT IS EQUAL TO THE RATE AT WHICH THE MAGNETIC FLUX THROUGH THE CIRCUIT IS CHANGING WITH TIME. So more rapid you move the coil, more will be the change in flux and hence more emf will be produced. So option D is the correct answer. I hope this long description will help you out.
Lapatulllka [165]3 years ago
5 0
_Award brainliest if helped!
The voltage produced is proportional to the rate of change of flux (magnetic field)
D. Move the magnet inside the coil of wire more rapidly.
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6 0
3 years ago
A water pipe tapers down from an initial radius of R1 = 0.21 m to a final radius of R2 = 0.11 m. The water flows at a velocity v
Aleks [24]

Answer:

0.116 m^3/s

Explanation:

The volume flow rate of a fluid in a pipe is given by:

Q=Av

where

A is the cross-sectional area of the pipe

v is the speed of the fluid

In this problem, at the initial point we have

v = 0.84 m/s is the speed of the water

r = 0.21 m is the radius of the pipe, so the cross-sectional area is

A=\pi r^2 = \pi (0.21 m)^2 =0.138 m^2

So, the volume flow rate is

Q=(0.138 m^2)(0.84 m/s)=0.116 m^3/s

8 0
3 years ago
Calculation using Ohm's Law: If a circuit has a voltage of 500 V and a resistance of 250 ohms, what is the current?
konstantin123 [22]

I = V / R

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Current = (500 V) / (250 ohms)

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6 0
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Trava [24]

Given data:

* The mass of the ball is 2 kg.

* The gravitational field strength at the surface of planet X is 5 N/kg.

Solution:

The weight of the ball on the planet X is,

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Substituting the known values,

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Lana71 [14]

Answer:

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Explanation:

By law of conservation of angular momentum

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f= final

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