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3 years ago

Moving a magnet inside a coil of wire will induce a voltage in the coil. How can the voltage in the coil be increased?

2 answers:

5 0

As the magnet is moved inside a coil of wire, the number of lines of magnetic field passing through the coil changes. Faraday stated that : it is the change in the number of field lines passing through the the coil of wire that induces emf in the loop. Specifically, it is the rate of change in the number of magnetic field lines passing through the loop that determines the induced emf. There is a term called magnetic flux same as electric flux, this magnetic flux can be a measure of the number of field lines passing through a surface. It is given by ( Φ=ΣB. dA. Where B is magnetic field and dA is small elementary area). The induced emf is given by (ξ = dΦ/dt). This equation states that THE MAGNITUDE OF THE INDUCED CURRENT IN A CIRCUIT IS EQUAL TO THE RATE AT WHICH THE MAGNETIC FLUX THROUGH THE CIRCUIT IS CHANGING WITH TIME. So more rapid you move the coil, more will be the change in flux and hence more emf will be produced. So option D is the correct answer. I hope this long description will help you out.

Lapatulllka [165]3 years ago

5 0

_Award brainliest if helped!
The voltage produced is proportional to the rate of change of flux (magnetic field)
D. Move the magnet inside the coil of wire more rapidly.

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2 years ago

A building made with a steel structure is 565 m high on a winter day when the temperature is 0◦F. How much taller is the buildin

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To solve this problem we apply the thermodynamic equations of linear expansion in bodies.

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$0\°F \Rightarrow (0-32)*\frac{5}{9} = -17.77\°C$

$103\°F \Rightarrow (103-32)*(\frac{5}{9})= 39.44\°C$

The coefficient of thermal expansion given is

$\alpha = 1.1*10^{-5}/\°C$

The initial length would be,

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Replacing we have to,

$\Delta L = L_0 \alpha \Delta T$

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