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3 years ago

What should you do when fueling an outboard boat with a portable tank?

Physics

2 answers:

bonufazy [111]3 years ago

7 0

Answer:

Connect the outboard boat to the earth

Explanation:

During re-fueling, small charges are generated. These charges result in some small electrostatics being generated. The generated static energy results in small electric sparks. If the object is not properly earthed, the will be a fire even from a very small spark. Thus, an earth system is needed to prevent a fire from taking place. The earth absorbs excess electrons. This prevents fires from taking place.

olasank [31]3 years ago

4 0

The portable tank should be connected to earth to neutralise rhe charges to prevent sudden discharge which may cause sparks and lead to fire.

You might be interested in

(a) How many fringes appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit

Ainat [17]

Answer:

The number of fringe is z = 3 fringes

The ratio is $I = 0.2545I_o$

Explanation:

From the question we are told that

The wavelength is $\lambda = 600 nm$

The distance between the slit is $d = 0.117mm = 0.117 *10^{-3} m$

The width of the slit is $a = 35.7 \mu m = 35.7 *10^{-6}m$

let z be the number of fringes that appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern is and this mathematically represented as

$z = \frac{d}{a}$

Substituting values

$z = \frac{0.117*10^{-3}}{35.7 *10^{-6}}$

z = 3 fringes

From the question we are told that the order of the bright fringe is n = 3

Generally the intensity of a pattern is mathematically represented as

$I = I_o cos^2 [\frac{\pi d sin \theta}{\lambda} ][\frac{sin (\pi a sin \frac{\theta}{\lambda } )}{\pi a sin \frac{\theta}{\lambda} } ]$

Where $I_o$ is the intensity of the central fringe

And Generally $sin \theta = \frac{n \lambda }{d}$

$I = I_o co^2 [ \frac{\pi (\frac{n \lambda}{d} )}{\lambda} ] [\frac{\frac{sin (\pi a (\frac{n \lambda}{d} ))}{\lambda} }{\frac{\pi a (\frac{n \lambda}{d} )}{\lambda} } ]$

$I = I_o cos^2 (n \pi)[\frac{\frac{sin(\pi a (\frac{n \lambda}{d} ))}{\lambda} )}{ \frac{ \pi a (\frac{n \lambda }{d} )}{\lambda} } ]$

$I = I_o cos^2 (3 \pi) [\frac{sin (\frac{3 \pi }{6} )}{\frac{3 \pi}{6} } ]$

$I = I_o (1)(0.2545)$

$I = 0.2545I_o$

6 0

3 years ago

Select the correct answer from the drop-down menu. anne applies a force on a toy car and makes it move forward. what can be said

nalin [4]

Answer:

The forces could be gravity, friction between the car and the ground, the force Katie is applying and the normal reaction.

6 0

2 years ago

Una pelota de voleibol de 0.45 kg es impactada (golpeada) por una fuerza de 80 N. ¿ Cuál es la aceleración que experimenta la pe

KIM [24]

Answer:

a = 177.77 [m/s^2]

Explanation:

Este es un problema relacionado con la segunda ley de Newton. La cual nos dice que la sumatoria de fuerzas aplicada sobre un cuerpo debe ser igual al producto de la masa por la aceleración.

De esta manera tenemos:

F = m*a

F = fuerza = 80 [N]

m = masa = 0.45 [kg]

80 = 0.45 * a

a = 80 / 0.45

a = 177.77 [m/s^2]

5 0

3 years ago

How does the electrical force relate to the charge of an object?

Akimi4 [234]

Answer:

The electrical force is directly proportional to the charge

Explanation:

The electrical force between two object is directly proportional to the net charge on each object and inversely proportional to the square of the distance between them

6 0

3 years ago

The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:

lutik1710 [3]

Answer:

At $t = 1\; \rm s$ , the particle should have a velocity of $-8\; \rm m \cdot s^{-1}$ .
At $t = 2\; \rm s$ , the particle should have a velocity of $-1\; \rm m \cdot s^{-1}$ .
At $t = 3\; \rm s$ , the particle should have a velocity of $\displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}$ .

For $a > 0$ , at $t = a \; \text{second}$ , the particle should have a velocity of $\displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}$ .

Explanation:

Differentiate the displacement of an object (with respect to time) to find the object's velocity.

Note that the in this question, the expression for displacement is undefined (and not differentiable) when $t$ is equal to zero. For $t > 0$ :

$\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}$ .

This expression can then be evaluated at $t = 1$ , $t = 2$ , and $t = 3$ to obtain the required results.

6 0

3 years ago