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klio [65]
3 years ago
11

Please help 16-20 thanks

Chemistry
1 answer:
MaRussiya [10]3 years ago
3 0
16.  FALSE
17. TRUE
18. FALSE
19. TRUE
20.  TRUE
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Aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge. Please select the best answer fr
Luden [163]
<h2>Answer:</h2>

True

<h2>Explanation:</h2>

we can describe aptitude as an innate ability of a person to do something. There are different aptitude test in which we test the skills and ability to do different work or his attitude toward success or failure.

So, we can say that aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge.

4 0
3 years ago
Read 2 more answers
Use the equation: 2Mg + O2→ 2MgO
ludmilkaskok [199]

Answer:

3 moles of O2 needed

Explanation:

2 moles of Mg   to one mole O2

   so 3 moles of O2 needed

6 0
1 year ago
You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10
natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

<u><em>q = 3,14x10⁸ J of heat are required</em></u>

<u><em /></u>

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = <em>18,8 kg of wood are required</em>

<em></em>

I hope it helps!

5 0
3 years ago
The volume of carbon gas at 5.0 ATM was measured to be 363 ml. What will the pressure be if the volume is change to .00020 ml?
aleksley [76]

Answer:

The answer to your question is P2 = 9075000 atm

Explanation:

Data

Pressure 1 = P1 = 5 atm

Volume 1 = V1 = 363 ml

Pressure 2 = P2 = ?

Volume 2 = 0.0002 ml

Process

To solve this problem use Boyle's law

                 P1V1 = P2V2

-Solve for P2

                 P2 = P1V1/V2

-Substitution

                  P2 = (5 x 363) / 0.0002

-Simplification

                  P2 = 1815 / 0.0002

-Result

                 P2 = 9075000 atm

5 0
3 years ago
There is a 50 g sample of ra-229. It has a half-life of 4 minutes.how much will be left after 12 minutes? a. 3.13 g b. 6.25 g c.
polet [3.4K]

It's B. 6.25

first divide 50/2

then divide 25/2

after that divide 12.5/2

Then you get 6.25

Hope it helps!

3 0
3 years ago
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