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3 years ago

Walters weekly take home pay is $354.90, which is 78% of his gross pay (before deductions). what is Walter's weekly gross pay?

Mathematics

1 answer:

Butoxors [25]3 years ago

7 0

$432.978 or $432.98 is the answer

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Sunny made 2 pitchers of strawberry smoothies for the science club. If each person got One-fifth of a pitcher, how many science

krek1111 [17]

Answer:

Answer:

The anwser is 2

Step-by-step explanation:

1 for each person

7 0

3 years ago

Read 2 more answers

Did you hear about the kidnapping?

Ganezh [65]

Answer:

69,420

Step-by-step explanation:

._. you stole the egg from the chicken didn't you

he woke up bc you threw the egg at his face

kid + napping... ok i get it now im slow

6 0

3 years ago

I need help on this please

Leya [2.2K]

The expression we have is:

$2xy\cdot xy^2$

And we are given some values for x and y:

$\begin{gathered} x=2 \\ y=4 \end{gathered}$

The first step will be to substitute the given values into the expression:

$2(2)(4)\cdot(2)(4)^2$

The next step is to solve 4^2 which is equal to 16:

$2(2)(4)\cdot(2)(16)$

And then we solve the multiplications, 2(2)(4) is equal to 16 and (2)(16) is equal to 32:

$16\cdot32$

Solving this final multiplication we get the result:

$512$

Answer: 512

8 0

1 year ago

Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),

amm1812

Answer:

Step-by-step explanation:

Approximate the integral $\int\int\limits_R {f(x,y)} \, dA$ by dividing the region $R$ with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i$

Since all are equal squares, so $\delta A_i=1$ for every $i$

$\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24$

Thus, $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24$

Evaluating the iterate integral $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.$