The answer is real and smaller than the object. The image point of the top of the object is the point where the two refracted rays intersect. Tracing the entire image having the same distance from the mirror as the image of the top of the object and with the bottom on the principal axis. Hence, a real inverted image will be formed for an object outside the focal point.
Answer:
ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)
Explanation:
The potential difference while moving from point A to Point B is given as follows:

where,
ΔV = potential difference from A to B = ?
= Potential at point A = 
= Potential at point B = 
Therefore,

where,
k = Colomb's Constant = 9 x 10⁹ N.m²/C²
q = magnitude of charge = 4.88 x 10⁻⁸ C
= distance of point A from charge = 1.36 m
= distance of point B from charge = 0.538 m
Therefore,

<u>ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)</u>
D) carbon dioxide because it makes more sense